Taking point (0,-2) of graph one and replacing in the equation;
2x+3y=6
2(0)+3(-2)=6
-6=6
So graph isn't the required graph.
Taking point (0,2) of graph 2;
2x+3y=6
2(0)+3(2)=6
6=6
So, graph 2 is the required graph.
Answer:
b and d/ a and c
Step-by-step explanation:
Answer:
y - (-3) = -8/5 (x - 2)
Step-by-step explanation:
-3 -5 = -8
2 - (-3) = 5
slope = -8/5
y - (-3) = -8/5 (x - 2)
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
Step-by-step explanation:
14^3