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3 years ago

The highest temperature recorded in the same city during the past year was

Chemistry

1 answer:

svp [43]3 years ago

7 0

Answer:

32.63°C

Explanation:

1K = -272.15°C

Formula:

305.78 K − 273.15 = 32.63°C

Hope this helps you out!! : )

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what volume (ml) of 3.0M NaOH is required to react with 0.8024-g copper ii nitrate?what mass of copper ii hydroxide will form as

Ksivusya [100]

The reaction between NaOH and Cu(NO₃)₂ is as follows

2NaOH + Cu(NO₃)₂ ---> 2NaNO₃ + Cu(OH)₂

Q1) stoichiometry of NaOH to Cu(NO₃)₂ is 2:1

this means that 2 mol of NaOH reacts with 1 mol of Cu(NO₃)₂

the mass of Cu(NO₃)₂ reacted - 0.8024 g

molar mass of Cu(NO₃)₂ is 187.56 g/mol

therefore the number of Cu(NO₃)₂ moles that have reacted

- 0.8024 g/ 187.56 g/mol = 0.00427 mol

according to the stoichiometry , number of NaOH moles - 0.00427 mol x 2

then number of NaOH moles that have reacted - 0.00855 mol

In a 3.0 M NaOH solution, 3 moles are in 1000 mL of solution

Then volume required for 0.00855 mol - 1000 x 0.00855 /3 = 2.85 mL

2.85 mL of 3.0 M NaOH is required for this reaction

Q2) Assuming that there's 100 % yield of Cu(OH)₂ , we can directly calculate the mass of Cu(OH)₂ formed from the number of moles of reactants that were used up.

Stoichiometry of Cu(NO₃)₂ to Cu(OH)₂ is 1:1

this means that 1 mole of Cu(NO₃)₂ gives a yield of 1 mole of Cu(OH)₂

the number of Cu(NO₃)₂ moles that reacted - 0.00427 mole

Therefore an equal amount of moles of Cu(OH)₂ were formed

Then amount of Cu(OH)₂ moles produced - 0.00427 mol

Mass of Cu(OH)₂ formed - 0.00427 mol x 97.56 g/mol = 0.42 g

A mass of 0.42 g of Cu(OH)₂ was formed in this reaction.

4 0

4 years ago

_________.__________ and___________ are energy science

Artist 52 [7]

Answer:

Chemical, Mechanical, and Nuclear Energy

Explanation:

3 0

3 years ago

An evaporation–crystallization process of the type described in Example 4.5-2 is used to obtain solid potassium sulfate from an

timofeeve [1]

Answer:

feed = 220.77 kg/s; maximum production rate of solid crystal = 416 kg/s; the rate of supplying fresh feed to obtain the production rate = 1.6

Explanation:

Material or mass balance can be used to estimate the mass flow rates of all the streams in the diagram shown in the attached file.

Overall balance: $M_{1} = 175 + 11M_{2}$

Water: $0.804M_{1} = 175 + 0.6M_{2}$

Using substitution method, we have:

$M_{1}$ = 220.77 kg/s

$M_{2}$ = 4.16 kg/s

The maximum production rate of solid crystal is $10M_{2}$ = 10*4.16 = 416 kg/s

Around evaporator:

$0.45M_{5} = 175$

$M_{5} = 175/0.45 = 389$ kg/s

Around the mixing point:

$M_{1} + M_{3} = M_{4} + M_{5}$

Solid crystal: $0.196M_{1} + 0.4M_{3} = M_{4}$

Using the last two equations, we can obtain:

$0.804M_{1} + 0.6M_{3} = M_{5}$

$0.6M_{3} = 389 - 0.804*220.77 = 389 - 177.5 = 211.5$

$M_{3} = 211.5/0.6 = 352.5$ kg/s

The rate of supplying fresh feed to obtain the production rate is:

$\frac{M_{3}}{M_{1}}$ = 352.5/220.77 = 1.6

7 0

4 years ago

A fossil is found to have a 14 C 14C level of 70.0 70.0 % compared to living organisms. How old is the fossil?

natulia [17]

Answer:

The age of the fossil be $2.1987\times 10^{4} years$ .

Explanation:

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$N_o$ = initial mass of isotope C-14 = x

N = mass of the parent isotope left after the time, (t) = 70.0% of x=0.07x

$t_{\frac{1}{2}}$ = half life of the isotope C-14 = 5730 years

$\lambda$ = rate constant

Let the age of the fossil be t.

Now put all the given values in this formula, we get t :

$0.07x=x\times e^{-(\frac{0.693}{5730 years})\times t}$

$t=2.1987\times 10^{4} years$

The age of the fossil be $2.1987\times 10^{4} years$ .

8 0

3 years ago

What is a scientific problem in<br> the world that really bugs you

Korolek [52]

Answer:

A scientific problem is something you don't understand but you can do an experiment to help you understand. Scientific problems are usually based on observation of scientific phenomena. Here is some advice to help you identify a scientific problem you can address by designing your own experiment.

Explanation:

Example of a scientific problem are Clean Drinking Water.

6 0

3 years ago