Ask question

Ask question

All categories

3 years ago

12

What did scientists create using scientific measurements?

1 answer:

Alexxx [7]3 years ago

3 0

Answer:

lines?

Explanation:

You might be interested in

Question 1 (1 point)

Dmitry [639]

1). trajectory

2). person sitting in a chair

3). 490 meters

4). 65 m/s

5). False. The projectile's displacement, velocity, and acceleration have vertical and horizontal components, but the projectile doesn't.

6). False

7). The vertical component of a projectile doesn't change due to gravity, but the vertical components of its displacement, velocity, and acceleration do.

The vertical components do NOT equal the horizontal components.

8). Decreasing if you include the effects of air resistance. Constant if you don't. Gravity has no effect on horizontal velocity.

9). We can't see the simulation. But if the projectile doesn't have jets on it, then as it travels upward, its vertical velocity must decrease, because gravity is trying to not let it get away.

10). We can't see the simulation. But if the projectile is traveling downward, we would call that "falling", and its vertical velocity must increase, because gravity is pulling it downward.

6 0

3 years ago

Read 2 more answers

Can someone do this assignment for me about <br> force

trasher [3.6K]

Answer:

Newtons 3sd law

Force = mass × acceleration

3rd photo about momentum

4 0

3 years ago

Can anyone answer this fast pls

nekit [7.7K]

I believe the answer would be 4.5. because it wouldnt be c or d. and 2 seems too small.

3 0

3 years ago

A point charge of +3 C is located at the origin of a coordinate system and a second point charge of -6 C is at x = 1.0 m. At w

Butoxors [25]

Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

$V_{E} = \frac{K*q}{r}$

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

$V_{1} + V_{2} = 0$

$K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0$ (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge

By replacing r₁ = 1 - r₂ into equation (1) we have:

$K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0$ (2)

By solving equation (2) for r₂:

$r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m$

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!

8 0

3 years ago

5. You are skateboarding on top of a small hill and take a break. You have 100 J of potential energy. If

Sholpan [36]

Given the potential energy of 100 J, the height of the hill is 0.128 m (12.8 cm)

Explanation:

The gravitational potential energy of an object is given by:

$U=mgh$

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

In this problem, we have

U = 100 J is the potential energy of the person

$g=9.8 m/s^2$ is the acceleration of gravity

m = 80 kg is the mass of the person

Solving for h, we find at what height the person is:

$h=\frac{U}{mg}=\frac{100}{(80)(9.8)}=0.128 m = 12.8 cm$

Learn more about gravitational potential energy here:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

5 0

3 years ago