Answer:
Object A has the greater volume by 1.6 cm³.
Explanation:
Density = mass / volume
Solving for volume:
Volume = mass / density
For object A:
V = 12 g / (3 g/cm³)
V = 4 cm³
For object B:
V = 12 g / (5 g/cm³)
V = 2.4 cm³
Object A has the greater volume by 1.6 cm³.
Answer:
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 seconds in the columns below.
Next, use the measured displacement and velocity values at t = 7.0 seconds and t = 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the following formula to interpolate and extrapolate. Remember, x and y here represent values on the x and y axes of the graph. The x values will really be time and the y values will be either displacement (x) or velocity (vx).
Explanation:
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 seconds in the columns below.
Next, use the measured displacement and velocity values at t = 7.0 seconds and t = 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the following formula to interpolate and extrapolate. Remember, x and y here represent values on the x and y axes of the graph. The x values will really be time and the y values will be either displacement (x) or velocity (vx).
This is the answer
Answer:
The mass of the planet Newtonia is .
Explanation:
It is given that,
Mass of the bob, m = 1.25 kg
Length of the simple pendulum, l = 185 cm = 1.85 m
Time taken by the simple pendulum, T = 1.42 s
The circumference of Newtonia is measured to be 51,4000 km. The time period of the simple pendulum is given by the formula as:
g is the acceleration due to gravity on planet Newtonia
For one complete cycle, T = 2.84 s
The formula of acceleration due to gravity on any surface is given by :
Since,
So, the mass of the planet Newtonia is . Hence, this is the required solution.
Answer:
Explanation:
The total charge is distributed over the two objects:
The plate and the rod must have . So the charge transferred from the plate to the rod is:
Number of electrons: