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Pachacha [2.7K]
2 years ago
15

Explain why some places can use only certain kinds of energy to generate electricity.

Physics
1 answer:
alukav5142 [94]2 years ago
6 0

Answer:

please mark me as a brainleast and follow me please my soster

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Answer:

the correct answer is torsional

Explanation:

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3 years ago
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Calculate the work done in lifting a 500-N
Mrac [35]

Answer:

1100Joules

Explanation:

Workdone = force x distance

Force= 500N

Distance = 2.2m

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= 1100Joules

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Uranium is a type of atom. In special circumstances that usually involve high amounts of energy, uranium can be broken. When thi
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When an atom of an element is broken down as a result of application of heat, the atom will be turn into an atom of another element. In the scenario given in the question above, the plutonium obtained is not the same as the uranium atom that was broken down, therefore, it will have properties that are completely different from that of the uranium atom.
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A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat
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Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

1200=92t+\dfrac{1}{2}\times4t^2

2t^2+92-1200=0

t=10\ sec

We need to calculate the velocity

Using equation of motion

v=u+at

Put the value into the formula

v=92+4\times10

v=132\ m/s

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

h'=h+ut-\dfrac{1}{2}at^2

Put the value into the formula

0=1200+132t-\dfrac{1}{2}\times9.8t^2

4.9t^2-132t-1200=0

t=34\ sec

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

t'=34+10

t'=44\ sec

Hence, The rocket above the ground is in 44 sec.

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3 years ago
The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is j. (formula: )
andreyandreev [35.5K]
1/2 m V-squared = j. j = 25 joules.
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3 years ago
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