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3 years ago

If an item that originally cost $13 is increased to $19, what is the percentage of increase in the item?

1 answer:

4 0

Original cost (OC) = $13

New cost (NC) = $19

Percentage increase = $\frac{NC - OC}{OC} *100 = \frac{19 - 13}{13} * 100 = \frac{6}{13} * 100$

= 46.15 %

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aliya0001 [1]

Answer:

P = 2(n - 6) + 2(n^2 - 8)

Step-by-step explanation:

Remembering that Area = Length times Width, we factor the given function

A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:

A = n^3 - 6n^2 - 8n + 48 factors as follows:

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We can label '(n - 6)' "width" and '(n^2 - 8'

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3 years ago

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An investor invests $2,500 into a mutual fund and earns 5.75% on the principle for each of three years. How much interest has ac

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Answer:

Interest in 3 years = $456.52

Step-by-step explanation:

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jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

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$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

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Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

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⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

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