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3 years ago

What is the total number of p electrons in a single phosphorus atom in its ground state?

Chemistry

2 answers:

Law Incorporation [45]3 years ago

7 0

Phosphorus has an electron configuration of [Ne} 3s2 3p3. Phosphorus has 9 electrons in the p orbital.

alekssr [168]3 years ago

7 0

Answer:

9 p-electrons

Explanation:

Phosphorus is a reactive chemical element that belongs to the group 15 and period 3 of the periodic table. It is a p-block element having atomic number 15.

The electronic configuration of phosphorus in the ground state is 1s² 2s² 2p⁶ 3s² 3p³.

Since, 6 electrons are present in the 2p subshell and 3 electrons are present in the 3p subshell.

Therefore, there are total 9 p-electrons in a phosphorus atom present in its ground state.

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True or False: There are five (5) of Newton's Laws of Motion *

kvasek [131]

Answer:

False

there is three

Explanation:

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3 years ago

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What is the percent by mass of water in Na2SO4 • 10H2O?

bulgar [2K]

We determine the percent by mass of water in the compound by dividing the mass of water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g.

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3 years ago

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Some table salt substitutes have potassium chloride in them. If you consume potassium chloride, are you truly eating potassium a

4vir4ik [10]

Answer:

You are consuming both

Explaination

2Na(s)+Cl two(g)

That gives us 2NaCl(s)

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3 years ago

Realice las siguientes conversiones: a) 72°F a °C, b) 213.8°C a °F, c)180°C a K, d) 315K a °F, e) 1750°F a K, f) 0K a °F.

bonufazy [111]

Answer:

a) 72 °F= 22.22 °C

b) 213.8 °C= 416.84°F

c) 180 °C= 453.15 °K

d) 315 °K= 107.33 °F

e) 1750 °F= 1227.594 °K

f) 0 °K= -459.67 °F

Explanation:

Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:

Fahrenheit a Celsius: $C=\frac{F-32}{1.8}$

Celsius a Fahrenheit: °F= °C*1.8 + 32
Celsius a Kelvin: °K= °C + 273.15
Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
Fahrenheit a Kelvin: $K=\frac{F-32}{1.8} + 273.15$

Entonces se obtiene:

a) 72 °F= $\frac{72-32}{1.8}$ =22.22 °C

b) 213.8 °C= 213.8*1.8 + 32= 416.84°F

c) 180 °C= 180°C + 273.15= 453.15 °K

d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F

e) 1750 °F= $\frac{1750-32}{1.8} + 273.15$ = 1227.594 °K

f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F

7 0

3 years ago

A sample of methane gas occupies 4.50 gallons at a temperature of 80.0 F. If the pressure is held constant, what will be the vol

Marat540 [252]

Answer:

21.19 L or 5.6 gallons

Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

1 gallon = 3.78541 L

4. 50 gallon = 3.785 L x 4.50

So,

initial volume V1 = 17.03 L

final Volume V2 = ?

initial Temperature T1 = 80° F

convert Temperature to Kelvin

T1 = ( 80° F -32) / 1.8 +273

T1 = 26.7° C + 273 = 299.7 K

final Temperature T2 = 100° C

convert Temperature to Kelvin

T2 = 100° C + 273 = 373 K

Solution:

This problem will be solved by using charles' law equation at constant pressure.

The formula used

V1 / T1 = V2 / T2

As we have to find out volume, so rearrange the above equation

V2 = V1 x T2 / T1

Put value from the data given and conversion information in above equation

V2 = 17.03 L x 373 K / 299.7 K

V2 = 21. 19 L

So the final volume of Methane gas = 21.19 L

Or for Volume in gallons

1 L = 0.26

21.19 x 0.264 = 5.6 gallons

7 0

3 years ago