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zalisa [80]
3 years ago
10

A gas container has a volume of 446.9 with a temp of 14c. When the volume is decreased to 238.7l the new temp is what

Chemistry
1 answer:
swat323 years ago
7 0

Answer:

\frac{V _{1}}{T _{1}}  =  \frac{V _{2}}{T _{2} }  \\  \frac{446.9}{(14 + 273)}  =  \frac{238.7}{T _{2} } \\ {T _{2}} =  \frac{238.7 \times 287}{446.9}  \\ {T _{2}} = 153.3 \: kelvin \\  = 119.7  \degree \: c

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