If the frequency of a wave is 68 hertz then the period of the wave is going to be

Chemistry

2 answers:

vova2212 [387]2 years ago

8 0

Answer:

0.01471 seconds

Explanation:

the period of a wave is given by 1/frequency.

tigry1 [53]2 years ago

6 0

The answer is 4.41x10^1 m.

Explanation:

You would use this formula to calculate it
λ = C/f

Where,

λ (Lambda) = Wavelength in meters

c = Speed of Light (299,792,458 m/s)

f = Frequency

So we have the frequency, 68 Hz, and we have the speed of light. Now we put it into the equation and it will look like this:

λ= (299,792,458 m/s) / (68 Hz)

λ= 4.41x10^1

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Gemiola [76]

Answer:

$m_{Ti}=13.0g$

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In this case, based on the given, we can infer that as titanium is hot and water cold, it cools down whereas the water is heated up, therefore, in terms of heat, we have that the heat lost by the titanium is gained by the water:

$-Q_{Ti}=Q_{H_2O}$

That in terms of mass, specific heat and temperatures is:

$-m_{Ti}Cp_{Ti}(T_2-T_{Ti})=m_{H_2O}Cp_{H_2O}(T_2-T_{H_2O})$

In such a way, for computing the mass of titanium, considering the heat capacity of water 4.18 J/g°C, we have:

$m_{Ti}=\frac{m_{H_2O}Cp_{H_2O}(T_2-T_{H_2O})}{-Cp_{Ti}(T_2-T_{Ti})} \\\\m_{Ti}=\frac{50.0g*4.18\frac{J}{g\°C}(22.6-20.0)\°C}{-0.54\frac{J}{g\°C}*(22.6-100.0)\°C} \\\\m_{Ti}=13.0g$