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Digiron [165]
3 years ago
13

If the frequency of a wave is 68 hertz then the period of the wave is going to be

Chemistry
2 answers:
vova2212 [387]3 years ago
8 0

Answer:

0.01471 seconds

Explanation:

the period of a wave is given by 1/frequency.

tigry1 [53]3 years ago
6 0
The answer is 4.41x10^1 m.

Explanation:

You would use this formula to calculate it
λ = C/f

Where,

λ (Lambda) = Wavelength in meters

c = Speed of Light (299,792,458 m/s)

f = Frequency

So we have the frequency, 68 Hz, and we have the speed of light. Now we put it into the equation and it will look like this:


λ= (299,792,458 m/s) / (68 Hz)

λ= 4.41x10^1


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Р<br> +<br> 02<br> =<br> P4O6 <br> balance the equation
sergejj [24]

To balance a chemical equation, both sides should have equal mass, or in other words both sides should have same number of atoms as to follow the conservation of mass rule.

P + O₂ = P₄O₆

LHS:

Number of Phosphorus atoms = 1 atom

Number of Oxygen atoms = 2 atoms

RHS:

Number of Phosphorous atoms = 4 atoms

Number of Oxygen atoms = 6 atoms

Also since P₄O₆ has the most number of atoms we will make the LHS equalize to P₄O₆.

Difference between Phosphorous atoms in LHS to RHS = 3

Since phosphorous is a monatomic we need 3 phosphorous atoms extra

Difference between Oxygen atoms is LHS to RHS = 4

But Oxygen is diatomic, so we need 4/2 = 2 Oxygen molecules

Now lets see if it is balanced

P + 3P + O₂ + 2O₂ -------> P₄O₆

               4P + 3O₂ ------>  P₄O₆

LHS:

Phosphorous atoms = 4 atoms

Oxygen atoms = 3 × 2 = 6 atoms

RHS:

Phosphorous atoms = 4 atoms

Oxygen atoms = 6 atoms

LHS = RHS

Therefore the balanced equation is 4P + 3O₂ =  P₄O₆

Happy to help :)

If you need more explanation or help in any other question, feel free to ask

3 0
2 years ago
CAVA Chemistry 302/303B Unit 2 Lab Report
mafiozo [28]
1 property

2 procedure

Results
5 0
3 years ago
The arrows in the image show the direction in which carbon is moving Which process of the carbon cycle is indicated
s344n2d4d5 [400]
The carbon cycle involves the circulation of carbon dioxide (CO2<span>) from the atmosphere into plants and other living organisms; the transfer of carbon from these organisms into other temporary storage pools, living or nonliving, containing organic and </span>inorganic<span> carbon compounds; and the return of CO</span>2<span> to the atmosphere </span>
8 0
3 years ago
What else is produced during the combustion of butane, C4H10?
denpristay [2]

Another product: CO₂

<h3>Further explanation</h3>

Given

Reaction

2C₄H₁₀ + 13O₂⇒ 8__+ 10H₂O

Required

product compound

Solution

In the combustion of hydrocarbons there can be 2 kinds of products

If there is excess Oxygen, you will get Carbon dioxide(CO₂) and water in the product

If Oxygen is low, you'll get Carbon monoxide(CO) and water

Or in other ways, we can use the principle of the law of conservation of mass which is also related to the number of atoms in the reactants and in the products

if we look at the reaction above, there are C atoms on the left (reactants), so that in the product there will also be C atoms with the same number of C atoms on the left

2C₄H₁₀ + 13O₂⇒ 8CO₂+ 10H₂O

5 0
3 years ago
Read 2 more answers
If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res
baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute = 27.1 g

M_{solute} = Molar mass of solute = 27.1 g/mol

W_{solvent} = Mass of solvent = 100 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m

Hence, the molality of the solution is 0.1 m.

8 0
3 years ago
Read 2 more answers
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