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Mariana [72]
4 years ago
7

Which of the following lists the elements in order of increasing malleability?

Chemistry
2 answers:
torisob [31]4 years ago
7 0

Answer:

The correct option is: <u>A. Se, Sb, Sn  </u>            

Explanation:

Malleability is the physical property of a chemical element, that allows it to change its shape or form thin sheets, when pressure or stress is applied.

It is a characteristic property of a metal. Mettaloids and non-metals are not malleable in nature, as they are brittle.

Since, Selenium (Se) is a non-metal, it is <u>non-malleable</u>.

Antimony (Sb) is a metalloid, it is <u>non-malleable.</u>

Tin (Sn) is a metal, it is <u>malleable.</u>

Therefore, <u>the increasing order of malleability </u>is: <u>A. Se, Sb, Sn</u><u>.</u>

Juliette [100K]4 years ago
4 0

The answer would be (B) Sb, Sn, Se.

The periodic table may look like a confusing checkerboard of elements, but they are categorized in more ways than you may know.

For malleability, we look for metals. Metals/metallic elements have characteristics like electrical conductivity, <u>malleability</u>, ductility, and other physical characteristics like luster. The more an element is metallic, the more of these characteristics it will have.

So to answer this question, you simply have to see what kind of elements these are:

Sb, 51 (Antimony): <em>Metalloid</em>

Sn, 50 (Tin): <em>Transition Metal</em>

Se, 34 (Selenium): <em>Non-Metal</em>

Therefore, Antimony will have more metal characteristics than the rest, putting it at the top. Selenium is a non-metal, so that goes at the bottom, and Tin will be second.

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3 years ago
A particular reactant decomposes with a half‑life of 109 s when its initial concentration is 0.280 M. The same reactant decompos
Sophie [7]

Answer:

The order of reaction is 2.

Rate constant is 0.0328 (M s)⁻¹

Explanation:

The rate of a reaction is inversely proportional to the time taken for the reaction.

As we are decreasing the concentration of the reactant the half life is increasing.

a) For zero order reaction: the half life is directly proportional to initial concentration of reactant

b) for first order reaction: the half life is independent of the initial concentration.

c) higher order reaction: The relation between half life and rate of reaction is:

Rate = \frac{1}{k[A_{0}]^{(n-1)}}

Half life =K\frac{1}{[A_{0}]^{(n-1)} }

\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }

where n = order of reaction

Putting values

\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}

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Hence n = 2

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Putting values

231=\frac{1}{K(0.132)}

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3 years ago
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