A rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s = 120t - 4t2 meters in t seco
1 answer:
Answer:
Step-by-step explanation:
Given that a rock is thrown vertically upward from the surface of an airless planet. It reaches a height of
where t is expressed in seconds
The rock goes upto a height where the velocity becomes 0 and then it starts falling down by gravity
Velocity at time t = s'(t) =
This becomes 0 when t =15 seconds
Hence at 15th second the rock starts falling and upto
s(15) = metres high it goes
The time taken to reach highest point is = 15 seconds.
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Option B:
The 12th term is 354294.
Solution:
Given data:
and
To find
The given sequence is a geometric sequence.
The general term of the geometric sequence is .
If we have 2 terms of a geometric sequence and
(n > K),
then we can write the general term as .
Here we have and
.
So, n = 7 and k = 4 ( 7 > 4)
This can be written as
Taking cube root on both sides of the equation, we get
r = 3
Hence the 12th term of the geometric sequence is 354294.