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Vedmedyk [2.9K]
3 years ago
15

A rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s = 120t - 4t2 meters in t seco

nds. How high does the rock go? How long does it take the rock to reach its highest point?
Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that a rock is thrown vertically upward from the surface of an airless planet. It reaches a height of s(t) = 120t - 4t^2

where t is expressed in seconds

The rock goes upto a height where the velocity becomes 0 and then it starts falling down by gravity

Velocity at time t = s'(t) = 120-8t

This becomes 0 when t =15 seconds

Hence at 15th second the rock starts falling and upto

s(15) = 120(15)-4(15^2)\\= 900 metres high it goes

The time taken to reach highest point is = 15 seconds.

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3 0
3 years ago
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FinnZ [79.3K]

Answer:i think its -5 because if you subtract 5 from 10 then its five hnd a negative times a negative is a positive

Step-by-step explanation:

3 0
3 years ago
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Sergeeva-Olga [200]
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What is the middle term of the product of (x + 5)(x + 2)? A.7x B.10x C.18x
torisob [31]
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3 years ago
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