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3 years ago

11

What are gamma rays? How are they used?

2 answers:

Vedmedyk [2.9K]3 years ago

4 0

Answer:

Gamma rays and its uses are discussed below.

Explanation:

Characteristics of Gamma rays

Radiation of short wavelength and high frequency.
Gamma rays do not deflect in a magnetic field.
Gamma rays have strong penetration energy

Uses of Gamma rays

Medical: Gamma rays are used as a medicine to kill the carcinogens cells and prevent them to grow again.
Industrial: Gamma rays are used in the industry to check the oil pipeline and discover the weak points.

Karo-lina-s [1.5K]3 years ago

3 0

I know it, X-rays<span>, </span>gamma rays<span> and beta particles are all </span>used<span> in medicine to treat internal organs. X-</span>rays<span> are produced by firing electrons at a metal target and </span>gamma rays<span> are emitted by the nucleus of radioactive atoms. </span>Gamma rays<span> are </span>used<span> to kill cancer cells, to sterilise medical equipment and in radioactive tracers.</span>

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Convert 15*c in Fahrenheit

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Answer:

it is 59 degrees Fahrenheit

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3 years ago

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Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init

Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ= $(m+\frac{1}{2})\frac{lamda}{n}$ ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= $\frac{3*lamda}{2}$

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= $\sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }$

δ= $\sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}$

δ= $\sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }$

δ= $\sqrt{4900+43^2}-\sqrt{4900+23^2}$

δ= $\sqrt{4900+1849}-\sqrt{4900+529}$

δ= $\sqrt{6749}-\sqrt{5429}$

δ= 82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= $\frac{3*lamda}{2}$

δ= 8.47

8.47 = $\frac{3*lamda}{2}$

λ = $\frac{8.47*2}{3}$

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3 0

3 years ago

A e B são dos blocos de massas 3,0 kg e 2,0 kg, respectivamente, que se movimentam juntos sobre uma superficie horizontal e perf

makvit [3.9K]

F = m*a

30 N = (ma + mb) * a

30 = 5*a

a = 6 m/s ^2

F de B em A

30 - F de B,A = ma * a

30 - F de B em A = 3 * 6

30 - 18 = F de B em A

12 = F de B em A

Resposta: 6 m/s^2 e 12N

Bate com o gabarito, man? Ou eu tô viajando aqui?

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3 years ago

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Answer:

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3 years ago

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<span>reflection, rotation, translation</span>

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