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kumpel [21]
3 years ago
5

Any push or pull on an object is Question 5 options: Acceleration Velocity Force Inertia

Physics
2 answers:
Kobotan [32]3 years ago
8 0
This would be force. Acceleration is increasing the speed in an object and velocity is how fast an object is going. Also, inertia basically says that an object will stay at rest or in motion unless an outside force acts on it. So, for example, a ball will stay in the air unless gravity acts on it and pulls it down. By definition, force is any action, unopposed (or by itself without any other forces that would do the opposite) will change the motion of an object, so this definitely makes the most sense for the question. Hope this helps!
densk [106]3 years ago
7 0
The answer is Force. To back it up, I just took the quiz with Force marked as the answer and it was correct.
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Which is a unit of pressure? A. gram B. Kilopascals C. Newtons D. Kilograms
Finger [1]

B. Kilopascals.

A kilopascal equals to 1,000 pascals; and a pascal is equal to a force of 1 newton per square meter.

Meanwhile,

- a gram and a kilogram are both units of measurement for mass, and

- a newton is a unit of measurement for force.

6 0
3 years ago
What would a distance-versus-time graph look like for the moving object in part (b)?
liberstina [14]
A distance-versus-time graph for the moving object would curve upward for acceleration and curve downward for deceleration
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3 years ago
olivia is taking pictures of the ocean on the edge of a cliff when she accidentally drops her phone. The phone hits the water at
In-s [12.5K]

The cliff is 12.71m tall.

Why?

Before solving the problem, we must remember that the phone was dropped, it means that there is no initial velocity, also, the acceleration acting on the phone is the acceleration due to gravity.

So, to find how tall is the cliff, we can use the following equations:

y=y_o+v_o*t-\frac{1}{2}g*t^{2}\\\\v_f=v_o+g*t

t=\frac{v_f}{g} \\\\t=\frac{-15.75\frac{m}{s}}{-9.81\frac{m}{s^{2}}}=1.61s

Now that we know the time, we can calculate how tall is the cliff:

y=y_o+v_o*t+\frac{1}{2}g*t^{2}\\\\y=0+0*1.61s-\frac{1}{2}*(-9.81\frac{m}{s^{2}})*(1.61s)^{2}\\\\y=12.71m

Hence, we have that the cliff is 12.71m tall.

Have a nice day!

3 0
4 years ago
. An aeroplane takes 30 min to travel from Biratnagar to Kathmandu. If the air distance between
Nadya [2.5K]

<u>Answer:</u>

average velocity = \bf 900 \space\ km/h

<u>Explanation:</u>

We can find the average velocity using the following equation:

\boxed{average \space\ velocity = \frac{total \space\ distance  \space\  travelled}{ \space\ time  \space\ taken}} .

In this case:

• total distance travelled = 450 km

• time taken = 30 min = 0.5 h

Substituting these values into the equation:

average \space\ velocity = \frac{450 \space\ km }{ 0.5 \space\ h}

                          ⇒ \bf 900 \space\ km/h

8 0
2 years ago
Wave length of a infra red wave
alexdok [17]

Answer:

780 nm - 1000 µm.

Explanation:

i surched it up

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