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6 months ago

which of the following instruments measures air pressure? group of answer choices barometer hygrometer radiometer thermometer

1 answer:

4 0

The tool used to gauge atmospheric pressure is a barometer. Concerning the device used to gauge air pressure, we have been questioned.

Mercury is used in barometers. A reservoir of mercury is compressed by atmospheric pressure, and depending on the force of the air, the mercury is propelled up into the tube to a specific height. A straightforward barometer consists of a long glass tube that is filled with mercury and is closed at one end and open at the other. As most cases, the air pressure is expressed in mm Hg.
By delivering quick, precise information on a range of metrics, Radiometer's products and solutions aid in the diagnosis and treatment of critically ill hospital patients.

A hygrometer is a device that gauges the moisture content of soil, air, or restricted spaces. Measurements of other quantities, such as temperature, pressure, mass, or a mechanical or electrical change in a substance as moisture is absorbed, are typically used as the basis for humidity measurement systems.
Voltmeters are used to measure voltages, while thermometers measure temperature.

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When is a hypothesis formed in the process of conducting an experiment?

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Because you need to have a guess to know what to argue or explain in your experiment

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2 years ago

A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processe

Allushta [10]

To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.

Mathematically this expression can be given as

$P = \sigma Ae\Delta T^4$

Where

A = Surface area of the Object

$\sigma =$ Stefan-Boltzmann constant

e = Emissivity

T = Temperature (Kelvin)

Our values are given as

$A = 1.36m^2$

$\Delta T^4 = T_2^4 -T_1^4 = 307^4-T_1^4$

$\sigma = 5.67*10^{-8} J/(s m^2 K^4)$

$P = 122J/s$

$e = 0.7$

Replacing at our equation and solving to find the temperature 1 we have,

$P = \sigma Ae\Delta T^4$

$P = \sigma Ae (T_2^4 -T_1^4)$

$122 = (5.67*10^{-8})(1.36)(0.7)(307^4-T_1^4)$

$T_1 = 285.272K = 12.122\°C$

Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C

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2 years ago

How does inertia affect a person who is not wearing a seatbelt during a collision?

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En caso de una colisión de bajo nivel de gravedad podría golpearse con el tablero del carro o en la parte del sillón (si esta sentado en la parte trasera). Pero si es muy grave la colisión podría salirse del carro por el cristal.

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3 years ago

Read 2 more answers

A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational

a_sh-v [17]

Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

Rock: $F = 49.06N$

Pebble: $F = 29.44N$

(b)Calculate the magnitude of the acceleration of each object when released.

Rock: $a =9.8m/s^{2}$

Pebble: $a =9.8m/s^{2}$

Explanation:

The universal law of gravitation is defined as:

$F = G\frac{m1m2}{r^{2}}$ (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

Case for the rock $m = 5.0 Kg$ :

m1 will be equal to the mass of the Earth $m1 = 5.972×10^{24} Kg$ and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth $r = 6371000m$ .