Answer: Jake is 9 and his dad is 33.
Step-by-step explanation: 9x3=27+6=33 9+33=42
Given:
The table of values is
x y
-4 2
-3 5
-2 8
-1 11
To find:
The slope of the line that contains these points.
Solution:
From the given table consider any two point.
Let the line passes through the points (-4,2) and (-3,5). So, the equation of the line is
Using distributive property, we get
Therefore, the required equation of line is .
Length of AB: 8 - - 6 = 14
Mid point at half length: 14/2 =7
—>Point G
Answer:
-132
Step-by-step explanation:
When you plug in -8 to every x you get -2(8)^2+2(8)-20 which gives you -132.
Let's make clear the question:
"<span>During August, Boxer Company sells $364,000 in merchandise that has a one year warranty. Experience shows that warranty expenses average about 5% of the selling price. The warranty liability account has a credit balance of $12,000 before adjustment. Customers returned merchandise for warranty repairs during the month that used $8,600 in parts for repairs. The entry to record the estimated warranty expense for the month is:
a) Debit Estimated Warranty Liability $18,200; credit Warranty Expense $18,200.
b) Debit Warranty Expense $6,200; credit Estimated Warranty Liability $6,200. c) Debit Warranty Expense $18,200; credit Estimated Warranty Liability $18,200.
d) Debit Warranty Expense $14,800; credit Estimated Warranty Liability $14,800.
e) Debit Estimated Warranty Liability $8,600; credit Warranty Expense $8,600." </span>
First, calculate the average warranty expenses:
364000 × 5 ÷ 100 = 18200$
This amount has to be recorded both as a debit (debit warranty expenses) and as a credit (credit estimated warranty liability).<span>
Therefore, the correct answer is:
</span><span>c) Debit Warranty Expense $18,200; credit Estimated Warranty Liability $18,200.</span>