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Romashka [77]
3 years ago
13

an object 8.25 cm from a lens creates a virtual image of magnification 2.40 what is the focal length of the lens (mind your minu

s sign) (unit=cm)
Physics
1 answer:
murzikaleks [220]3 years ago
5 0

Answer:

Focal length of the lens is 14.14 cm

Explanation:

As we know that the image formed due to lens is virtual image

so here we have

M = 2.40

now we have

\frac{d_i}{d_o} = 2.40

now we have

distance of object is 8.25 cm

so we have

d_i = 8.25(2.40) = 19.8 cm

now by lens formula

\frac{1}{d_i} - \frac{1}{d_o} = \frac{1}{f}

\frac{1}{-19.8} - \frac{1}{-8.25} = \frac{1}{f}

f = 14.14 cm

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Answer:

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5 0
3 years ago
How does this app work
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6 0
3 years ago
an object of mass 8 kg is whriled round in a vertical circle of radius 2m with a constant speed of 6m/s .Then the maximum and mi
algol13

Answer:

Maximum Tension=224N

Minimum tension= 64N

Explanation:

Given

mass =8 kg

constant speed = 6m/s .

g=10m/s^2

Maximum Tension= [(mv^2/ r) + (mg)]

Minimum tension= [(mv^2/ r) - (mg)]

Then substitute the values,

Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N

Minimum tension= [8 × 6^2)/2 -(8×9.8)]

=64N

Hence, Minimum tension and maximum Tension are =64N and 2224N respectively

5 0
2 years ago
Please help ASAP! Thank you :)
puteri [66]

Answer:

magnitude of gravitational force between the Earth and the Sun at B is greater than that at A

Explanation:

Formula of gravitational force:

F = GMm/r^2

(r is the distance between 2 objects)

We see that r(B) < r(A) since at B, the Earth is closer to the Sun than at A

According to the Formula, the smaller r is, the greater F is

So, F(B) > F(A)

8 0
3 years ago
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