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Romashka [77]
4 years ago
13

an object 8.25 cm from a lens creates a virtual image of magnification 2.40 what is the focal length of the lens (mind your minu

s sign) (unit=cm)
Physics
1 answer:
murzikaleks [220]4 years ago
5 0

Answer:

Focal length of the lens is 14.14 cm

Explanation:

As we know that the image formed due to lens is virtual image

so here we have

M = 2.40

now we have

\frac{d_i}{d_o} = 2.40

now we have

distance of object is 8.25 cm

so we have

d_i = 8.25(2.40) = 19.8 cm

now by lens formula

\frac{1}{d_i} - \frac{1}{d_o} = \frac{1}{f}

\frac{1}{-19.8} - \frac{1}{-8.25} = \frac{1}{f}

f = 14.14 cm

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If the mass of B is m and the temperature change is the same, the mass of B will be 2m.

Explanation:

Q = mcT

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T = Q/mc

Plug this in equation 1.

M = 4Q/(2c × Q/mc)  = 4Q ÷ 2Q/m  = 4Q × m/2Q = 2m

6 0
3 years ago
Newton's law of gravity was inconsistent with Einstein's special relativity because
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Answer:

Mass and thus force depends on the reference frame chosen

Explanation:

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In order to observe Newton's law of gravity all the observer's in different reference frames must observe the same phenomena which could only be possible if time were absolute and in special relativity, time is not absolute.

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3 0
3 years ago
classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 128 feet per
ddd [48]

Answer:

t_1 = 0.28 s

t_2 = 7.72 s

Explanation:

Given that height of the projectile as a function of time is

h = -16 t^2 + 128 t + 112

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h = 147 ft

so from above equation

147 = -16 t^2 + 128 t + 112

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Answer:

D. 130 J

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Here Q_C  is the heat removed from the cold reservoir, W is the work required, that is, the energy required to remove the heat from the interior of the house, T_C is the cold temperature and T_H is the hot temperature. Recall use absolutes temperatures(273.15+^\circ C). Replacing and solving for W:

W=Q_c\frac{T_H-T_C}{T_C}\\W=2000J\frac{312.15K-293.15K}{293.15K}\\W=129.63J

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4 years ago
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-Ptolemy

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