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Naya [18.7K]
3 years ago
8

how long would it take for a radio wave sent from a space satellite circling mars to reach Earth? Assume that radio waves (a for

m of electromagnetic radiation) travel at the speed of light?
Physics
1 answer:
kati45 [8]3 years ago
3 0

Answer:

3 Minutes 2 seconds to 22 minutes 16 seconds

Explanation:

Lets assume the Mars to be at the closest distance to Earth. This distance (D) = 54.6 Million km

The signal travels at the speed of light, so speed of the signal (V) = 300000 km/s

So, the time (T) taken by the radio wave to reach Earth from Mars will be,

T = \frac{D}{V}

T = \frac{54600000}{300000}

Thus, T = 182 Sec = 3 Minutes 2 seconds.

The radio wave will take minimum 03 Minutes 02 seconds to reach Earth. Here is should be noted that the distance between the two planets keep on changing as they revolve around the Sun. There will come a point when Mars is farthest from Earth and the distance (D) will be 401 Million km. Then, the time will change to ,

T = \frac{401000000}{300000}

T = 1336.67 sec = 22.27 Minutes.

So the maximum time will be 22 minutes 16 seconds.

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an object is accelerated from a constant rate of 5.00 m/s squared what will be its speed after 8.00 seconds
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Answer: The answer to this question is velocity =40m/s

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A fully loaded Saturn V rocket has a mass of 2.92 x 106 kg. Its engines have a thrust of 3.34 x 107 N.
balandron [24]

<u>Complete Question:</u>

A fully loaded Saturn V rocket has a mass of 2.92 x 106 kg. Its engines have a thrust of 3.34 x 107 N. (8 marks)

a) What is the downward force of gravity on the rocket at blast-off?

b) What is the unbalanced force on the rocket at blast-off?

c) What is the acceleration of the rocket as it leaves the launching pad?

d) As the rocket travels upwards, the engine thrust remains constant, but the mass of the rocket decreases. Why?

e) Does the acceleration of the rocket increase, decrease, or remain the same as the engines continue to fire?

<u>Answer:</u>

a) -2.8616 \times 10^{7} N is the downward force of gravity on the rocket at blast-off.

b) 4.784 \times 10^{6} N is the unbalanced force on the rocket at blast-off

c) 1.638 \mathrm{m} / \mathrm{s}^{2} is the acceleration of the rocket as it leaves the launching pad

d) Because the propellant here is burned up, hence the mass of the rocket seems to be varied (total mass of all its parts). Thereby, the mass decreases when the rocket moves upward.

e) The acceleration of the rocket increases when engines continue to fire

<u>Explanation:</u>

Given:

Mass (m) =  2.92 \times 10^{6} \mathrm{kg}

a) In physics, weight can be defined as the applied force on a body by gravity. It is the product of mass (m) and gravity \left(g=9.8 \mathrm{m} / \mathrm{s}^{2}\right)

  \text { weight }(W)=m \times g=2.92 \times 10^{6} \times(-9.8)=28.616 \times 10^{6}=-2.8616 \times 10^{7} N

The negative sign indicates the downward force of gravity.

b) To find the unbalanced force on the rocket at blast-off,

Accelerating force,

   F_{a}=F+W=3.34 \times 10^{7}+\left(-2.8616 \times 10^{7}\right)=(3.34-2.8616) \times 10^{7}

   F_{a}=0.4784 \times 10^{7}=4.784 \times 10^{6} N

c) Newton’s second law of motion states that the object’s acceleration depends on two variable:

  • Directly proportionate to the object’s force existed
  • Inversely proportionate to the mass of the objects

The equation can be given as below,

    Force =m \times acceleration

    \text { Acceleration }=\frac{F_{a}}{m}=\frac{4.784 \times 10^{6}}{2.92 \times 10^{6}}=1.638 \mathrm{m} / \mathrm{s}^{2}

d) The pushing of rocket upward will happen as long as the engine gets fired. The propellant here is burned up, hence the mass of the rocket seems to be varied (total mass of all its parts). Thereby, the mass decreases (taotal mass) when the rocket moves upward.

e) The acceleration of the rocket increases when engines continue to fire

Let consider F_{a} is constant, mass gets decreasing, then the acceleration would be increasing (as mass and acceleration are inversely proportionate to each other) .

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