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3 years ago

A bowling ball has a mass of 5 kg. What happens to its momentum when its speed increases from 1 m/s to 2 m/s?

1 answer:

8 0

The linear momentum is given by $mv$ . Here $m$ is mass $v$ is velocity of the body. Given mass and velocities as $m=5,v_i=1,v_f=2$

Initial momentum is $mv_i=5*1=5$ and final momentum is $mv_f=5*2=10$ .

The correct answer is (A)

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user100 [1]

Answer:

$\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N$

Explanation:

The total force on the particle is given by

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Then, by replacing we have:

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where the cross product can be made with the determinant method.

Hope this helps!!

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3 years ago

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Wittaler [7]

Answer:

Explanation:

The force supplied by the train can be found by using the formula

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From the question we have

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We have the final answer as

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kolbaska11 [484]

Answer:

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