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Fantom [35]
4 years ago
12

A bowling ball has a mass of 5 kg. What happens to its momentum when its speed increases from 1 m/s to 2 m/s?

Physics
1 answer:
faltersainse [42]4 years ago
8 0

The linear momentum is given by mv. Here m is mass v is velocity of the body. Given mass and velocities as m=5,v_i=1,v_f=2

Initial momentum is mv_i=5*1=5 and final momentum is mv_f=5*2=10.

The correct answer is (A)

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You toss a conductive open ring of diameter d = 1.75 cm up in the air. The ring is flipping around a horizontal axis at a rate o
Mama L [17]

Answer:

The maximum emf induced in the ring

= (2.882 × 10⁻⁷) V

Explanation:

According to the law of electromagnetic induction, the emf induced in the ring is given by

E = N BA w sin wt

The maximum emf induced is

E = N BA w

B = 30.5 μT = (30.5 × 10⁻⁶) T

A = (πD²/4)

D = 1.75 cm = 0.0175 m

A = (π×0.0175²/4) = 0.000240625 m²

Nw = 2π × 6.25 = 39.29 rad/s

E = 30.5 × 10⁻⁶ × 0.000240625 × 39.29

E = (2.882 × 10⁻⁷) V

Hope this Helps!!!

8 0
3 years ago
Can you help with this please
Vlad1618 [11]
1 every light in your household is parallel this is useful bc as one goes out not all do as they would in a series circuit 2 plastic and glass they are common bc it does not let electricity travel from one place to another outside of it
8 0
3 years ago
Read 2 more answers
Generally the length of metre is equal all over the world why?​
erastova [34]

Answer:

It is an SI unit

Explanation:

The metre is defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second. The metre was originally defined in 1793 as one ten-millionth of the distance from the equator to the North Pole

8 0
4 years ago
What is the time required for an object starting from rest.
sashaice [31]
Time required for what?
6 0
2 years ago
The solid rod shown has a radius of 0.75 in. if it is subjected to the force the 500lb determine the max normal stress developed
Kipish [7]
The normal stress follows the formula written below:

σ = F/A

There are two types of stress, axial and tangential. Since we are only given with the dimension of the radius (and not the length), the possible stress is axial. So, the area is,

A = πr² = π(0.75 in)² = 1.767 in²

So,
σ = F/A = 500 lb/1.767 in² = <em>282.94 psi</em>
7 0
3 years ago
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