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4 years ago

A bowling ball has a mass of 5 kg. What happens to its momentum when its speed increases from 1 m/s to 2 m/s?

1 answer:

8 0

The linear momentum is given by $mv$ . Here $m$ is mass $v$ is velocity of the body. Given mass and velocities as $m=5,v_i=1,v_f=2$

Initial momentum is $mv_i=5*1=5$ and final momentum is $mv_f=5*2=10$ .

The correct answer is (A)

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A rod (length = 80 cm) with a rectangular cross section (1.5 mm × 2.0 mm) has a resistance of 0.20 Ω. What is the resistivity of

Andru [333]

Answer:

The resistivity of the material used to make the rod is ρ= 7.5 * 10⁻⁷ Ω.m

Explanation:

R= 0.2 Ω

L= 0.8 m

S= 1.5mm*2mm= 3 mm² = 3 * 10⁻⁶ m²

ρ = (R*S)/L

ρ= 7.5 * 10⁻⁷ Ω.m

7 0

3 years ago

A block of mass 0.84 kg is suspended by a string which is wrapped so that it is at a radius of 0.061 m from the center of a pull

lora16 [44]

Answer:

$E_l = 1.713 J$

Explanation:

Given data:

mass of block is $M_b = 0.84 kg$

radius of block = 0.061 m

moment of inertia is $6.20 \times 10^{-3} kg m^2$

D is distance covered by block = 0.65 m

speed of block is 1.705 m/s

From conservation of momentum we have

$M_b g D = \frac{1}{2} M_b v^2 + \frac{1}{2} I \omega^2 + E_{loss}$

$0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times 0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l$

solving for energy loss

$E_l = 1.713 J$

3 0

3 years ago

Points A and B lie above an infinite plane of negative charge that produces a uniform electric field of strength E=10 N/C. What

olasank [31]

There is no illustration of the problem provided but I'll attempt to provide an answer.

The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:

║E║ = ΔV/d

║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.

We are given the following values:

║E║= 10N/C

d = 3m

Plug these values in and solve for ΔV

10 = ΔV/3

ΔV = 30V

4 0

4 years ago

What happens to an electromagnetic wave when the frequency is doubled?

Artist 52 [7]

The product of (frequency) times (wavelength) is always
the same number (the speed of the wave).

So if the frequency is doubled, the wavelength has to drop to
half of what it was, in order to keep their product constant.

4 0

4 years ago

23 and 24 only please help!

Lilit [14]

Answer:

23: Acceleration 24:1m/s^2

Explanation:

$a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2$

7 0

3 years ago