Does 30,40 ,and 45 form a right triangle

Mathematics

1 answer:

Bingel [31]3 years ago

6 0

Nope the angles are two close

You might be interested in

NEED HELP ASAP PLEASE

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

So the first 1 on the left is A=2lw+2lh+2wh

Then the first 1 on the right the property you use is distribute

Then the rest I don’t know I’m sorry

4 0

3 years ago

a rectangle has a length that is nine feet less than four times its width. Its area is 90 ft. Algebraically determine the length

sammy [17]

Ok... after much confusion, I've come to the conclusion that you must have written the question wrong and it's actually the perimeter that is 90 feet so that's how I'm going to work it...

Width = w
Length = 4w - 9

P = 2w x 2L
90 = 2w + 2(4w - 9)
90 = 2w + 8w - 18
90 = 10w - 18
108 = 10w
108/10 = w
10 4/5 = w

Width is 10 4/5 ft

Length = 4w - 9
L = 4(10 4/5) - 9
L = 43 1/5 - 9
L = 34 1/5 ft

Length 34 1/5 ft Width 10 4/5 ft or
Length 34.2 ft and width 10.8 ft

6 0

3 years ago

Proove that <br>1/1-sin theta + 1/1+cos theta = 2×sec square theta

Rina8888 [55]

Step-by-step explanation:

We need to prove that,

$\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}=2\times \sec^2\theta$

Taking LHS,

$\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}\\\\=\dfrac{(1+\sin\theta)+(1-\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}\\\\=\dfrac{2}{1-\sin^2\theta}\\\\\text{As}\ 1-\sin^2\theta=\cos^2\theta\\\\=\dfrac{2}{\cos^2\theta}\\\\\text{As}\ \dfrac{1}{\cos^2\theta}=\sec^2\theta\\\\=2\sec^2\theta\\\\=RHS$

Hence, LHS = RHS.

4 0

3 years ago

What is -3/8, 5/16, -0.65, 2/4 from least to greatest

storchak [24]

-3/8, -0.65, 5/16, 2/4

8 0

3 years ago

Which set of x- and y-values represents a function

dolphi86 [110]

If Im correct I believe the answer is the last one

3 0

3 years ago