From the periodic table:
molar mass of Sn = 118.71 grams
molar mass of F = 18.99 grams
This means that:
molar mass of SnF2 = 118.71 + 2(18.99) = 156.69 grams
Therefore, 156.69 grams of SnF2 contains 37.98 grams of F. To know the amount of F in 36.5 grams of the compound, we will simply do a cross multiplication as follows:
mass of F = (36.6 x 37.98) / 156.69 = 8.847 grams
Answer:
15m
Explanation:
vi = 0
vf = 10
a = -9.8
10^2 = 0 + 2(-9.8)(x2-x1) = -5.1
20-5.1 = 14.9m = 15m
