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Nitella [24]
3 years ago
14

Starting at point 0, you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees. What is your heigh

t above the starting point? Answer in meters to the nearest centimeter
Physics
1 answer:
ira [324]3 years ago
5 0

Answer:

43.58 m

Explanation:

If you travel 500 m on a straight road that slopes upward at a constant angle of 5 degrees

Using trigonometry ratio

Sin 5 = opposite/hypothenus

Where the hypothenus = 500m

Opposite = height h

Sin 5 = h/500

Cross multiply

500 × sin 5 = h

h = 500 × 0.08715

h = 43.58m

Therefore, the height above the starting point is equal to 43.58m

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Answer:

A. True

Explanation:

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2 years ago
A parallel-plate vacuum capacitor has 8.60 J of energy stored in it. The separation between the plates is 3.80 mm . If the separ
creativ13 [48]

Answer:

Part a)

E = \frac{8.60}{2.62} = 3.28 J

Part b)

E = 2.62(8.60) = 22.5 J

Explanation:

As we know that the energy of capacitor when it is not connected to potential source is given as

U = \frac{Q^2}{2C}

As we know that initial energy is given as

8.60 = \frac{Q^2}{2C}

now we know that capacitance of parallel plate capacitor is given as

C = \frac{\epsilon_0A}{d}

now the new capacitance when distance is changed from 3.80 mm to 1.45 mm

C' = \frac{Cd}{d'}

C' = \frac{C(3.80)}{1.45}

C' = 2.62 C

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E = \frac{Q^2}{2(2.62C)}

E = \frac{8.60}{2.62} = 3.28 J

Part b)

Now if the voltage difference between the plates of capacitor is given constant

now the energy energy of capacitor is

U = \frac{1}{2}CV^2

8.60 = \frac{1}{2}CV^2

now when capacitance is changed to new value then new energy is given as

E = \frac{1}{2}C'V^2

E = \frac{1}{2}(2.62C)V^2

E = 2.62(8.60) = 22.5 J

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3 years ago
A car traveling on a straight road at 10 meters per second accelerates uniformly to a speed of 21 meters per second in 12 second
labwork [276]
21+10=31 because you can see that 21 and 10 are in metres while 12 is in seconds so 21+10=31 is the answer.
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2 years ago
An ocean liner leaves New York City and travels 18.0o north of east for 155 km. How far east and how far north has it gone? In o
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I’m sorry if i took up a lot of space, hope this is a valid approximate answer

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Can someone help with me 1,2,3 please I will mark brainless .
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Answer:

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