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sergeinik [125]

3 years ago

7

Which of the following should NOT be discussed during safety training

1 answer:

Juli2301 [7.4K]3 years ago

7 0

Is there suppose to be an image?

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O'Malley is riding on a bus which is moving at 10 m/s, and he throws a ball which he observes to be moving at 10 m/s relative to

Vikki [24]

Answer:

<em>20 m/s in the same direction of the bus.</em>

Explanation:

<u>Relative Motion </u>

Objects movement is always related to some reference. If you are moving at a constant speed, all the objects moving with you seem to be at rest from your reference, but they are moving at the same speed as you by an external observer.

If we are riding on a bus at 10 m/s and throw a ball which we see moving at 10 m/s in our same direction, then an external observer (called Ophelia) will see the ball moving at our speed plus the relative speed with respect to us, that is, at 20 m/s in the same direction of the bus.

3 0

3 years ago

A driver notices an upcoming speed limit change from 45 mi/h (20 m/s) to 25 mi/h (11 m/s). If she estimates

zloy xaker [14]

Answer:

-2.79 m/s²

Explanation:

Given:

v₀ = 20 m/s

v = 11 m/s

Δx = 50 m

Find: a

v² = v₀² + 2aΔx

(11 m/s)² = (20 m/s)² + 2a (50 m)

a = -2.79 m/s²

Round as needed.

8 0

3 years ago

A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?

Dafna11 [192]

Answer:

15m/s²

Explanation:

Given parameters:

Initial velocity = 10m/s

Final velocity = 40m/s

Time taken = 2s

Unknown:

Average acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time;

Acceleration = $\frac{Final velocity - Initial velocity }{time}$

Acceleration = $\frac{40 - 10}{2}$ = 15m/s²

6 0

3 years ago

A crow is flying horizontally with a constant speed of 2.70 m/s when it releases a clam from its beak. the clam lands on the roc

vovangra [49]

Part a)

in horizontal direction there is no gravity or no other acceleration

so in horizontal direction the speed of clam will remain same

$v_x = 2.70 m/s$

Part b)

In vertical direction we can use kinematics

$v_f = v_i + at$

$v_f = 0 + 2.1 * 9.8$

$v_f = 20.6 m/s$

part c)

if the speed of crow will be increased then the horizontal speed of the clam will also increase but there is no change in the vertical speed

5 0

3 years ago

The Hall effect can be used to calculate the charge-carrier number density in a conductor. A conductor carrying current of 2.0 A

marysya [2.9K]

Answer:

option D

Explanation:

given,

A conductor is carrying current = 2.0 A is 0.5 mm thick

Hall voltage = 4.5 x 10-6 V

uniform magnetic field = 1.2 T

density of the charge = n =?

hall voltage = $V_h =\dfrac{i\ B}{n\ e\ L}$

$n = \dfrac{i\ B}{V\ e\ L}$

$n = \dfrac{2 \times 1.2 }{4.5 \times 10^{-6}\times 1.6 \times 10^{-19} \times 0.5 \times 10^{-3}}$

n = 6.67 × 10²⁷ charges/m

hence the correct answer is option D

7 0

3 years ago