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vampirchik [111]
3 years ago
8

The student hung the plastic strip over a wooden rod

Physics
1 answer:
dimaraw [331]3 years ago
3 0

Answer:

The main force in play here is weight W, or m*g (where m is Mass and g is Gravity) that make up the main force acting downwards. This could also be referred to as the normal force.

Explanation:

From what we can see the plastic strip is at a certain angle. To which other forces, such as: friction, pull and the ones mentioned above come into play in this question.

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A WLAN transmitter that emites a 100 mW signal is connected to a cable with a 3dB loss. If the cable is connected to an antenna
irakobra [83]

Answer: 24 dBm

Explanation:

in the attachment

6 0
3 years ago
When a 12 newton horizontal force is applied to a box on a horizontal
sdas [7]

Answer:

ur mum

Explanation:

6 0
3 years ago
A parallel-plate air capacitor is made from two plates 0.210 m square, spaced 0.815 cm apart. it is connected to a 120 v battery
GuDViN [60]

Answer:

at the beginning: 2.3\cdot 10^{-10} F

when the plates are pulled apart: 1.1\cdot 10^{-10} F

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=k \epsilon_0 \frac{A}{d}

where

k is the relative permittivity of the medium (for air, k=1, so we can omit it)

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the permittivity of free space

A is the area of the plates of the capacitor

d is the separation between the plates

In this problem, we have:

A=0.210 m^2 is the area of the plates

d=0.815 cm=8.15\cdot 10^{-3} m is the separation between the plates at the beginning

Substituting into the formula, we find

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{8.15\cdot 10^{-3} m}=2.3\cdot 10^{-10} F

Later, the plates are pulled apart to d=1.63 cm=0.0163 m, so the capacitance becomes

C=(1)(8.85\cdot 10^{-12}F/m)\frac{0.210 m^2}{0.0163 m}=1.1\cdot 10^{-10} F

4 0
3 years ago
Một chất điểm khối lượng m=200g chuyển
MrMuchimi
Can you please translate to English?
8 0
2 years ago
All Physicsts over here plz help in these questions!!!!!!!!!
mrs_skeptik [129]
Hello!

First one we can use that PE=mgh so we have

4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m

Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have

g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2

Hope this helps. Any questions please ask. Thank you.
6 0
3 years ago
Read 2 more answers
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