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3 years ago

The student hung the plastic strip over a wooden rod

Physics

1 answer:

dimaraw [331]3 years ago

3 0

Answer:

The main force in play here is weight W, or m*g (where m is Mass and g is Gravity) that make up the main force acting downwards. This could also be referred to as the normal force.

Explanation:

From what we can see the plastic strip is at a certain angle. To which other forces, such as: friction, pull and the ones mentioned above come into play in this question.

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A bullet is fired with a velocity of 100 m/s from the ground at an angle of 60° with the horizontal. Calculate the horizontal ra

seraphim [82]

1) The horizontal range of the bullet is 884 m

2) The maximum height attained by the bullet is 383 m

Explanation:

The motion of the bullet is a projectile motion, which consists of two separate motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction

From the equation of motions along the x- and y- directions, it is possible to find an expression for the horizontal range covered by a projectile, and it is:

$d=\frac{u^2 sin 2\theta}{g}$

where

u is the initial speed of the projectile

$\theta$ is the angle of projection

$g=9.8 m/s^2$ is the acceleration of gravity

For the bullet in the problem, we have

u = 100 m/s (initial speed)

$\theta=60^{\circ}$ (angle)

Solving the equation, we find the horizontal range:

$d=\frac{(100)^2sin(2\cdot 60^{\circ})}{9.8}=884 m$

To find the maximum height, we have to analyze the vertical motion of the bullet. We can do it by using the following suvat equation:

$v_y^2 - u_y^2 = 2as$

where

$v_y$ is the vertical velocity of the bullet after having covered a vertical displacement of $s$

$u_y$ is the initial vertical velocity

$a =-g=$ is the acceleration (negative, since it points downward)

The vertical component of the initial velocity is given by

$u_y = u sin\theta$

Also, the maximum height s is reached when the vertical velocity becomes zero,

$v_y =0$

Substituting into the equation and re-arranging for s, we find the maximum height:

$s=\frac{u^2 sin^2 \theta}{2g}=\frac{(100)^2(sin 60^{\circ})^2}{2(9.8)}=383 m$

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0

4 years ago

A cube with sides of area 22 cm2 contains a 21.2 nanoCoulomb charge. Find the flux of the electric field through the surface of

VladimirAG [237]

Answer:

Explanation:

According to Gausses theorem, electric flux coming out of charge on all sides q is equal to

q / ε₀

q is charge , ε₀ is permittivity of air whose value is given by

8.85 x 10⁻¹²; q = 21.2 x 10⁻⁹ C

Putting the values we get

FLUX = $\frac{21.2\times10^{-9}}{8.85\times10^{-12}}$

2.4 x 10³ Nm²/C

3 0

3 years ago

The New England Merchants Bank Building in Boston is 152 mm high. On windy days it sways with a frequency of 0.20 HzHz , and the

kkurt [141]

Answer:

The total distance, side to side, that the top of the building moves during such an oscillation = 31 cm

Explanation:

Let the total side to side motion be 2A. Where A is maximum acceleration.

Now, we know know that equation for maximum acceleration is;

A = α(max) / [(2πf)^(2)]

So 2A = 2[α(max) / [(2πf)^(2)] ]

α(max) = (0.025 x 9.81) while frequency(f) from the question is 0.2Hz.

Therefore 2A = 2 [(0.025 x 9.81) / [((2π(0.2)) ^(2)] ] = 2( 0.245 / 1.58) = 0.31m or 31cm

3 0

3 years ago

Helpppppppp<br> ill give brainliest

Nina [5.8K]

Answer:

I believe the answer is

$B. \: 3 \: red, \: 8 \: yellow, \: 1 \: blue$

Explanation:

I may be incorrect because I used to do this a long time ago but I believe I am correct

HOPE THIS HELPS!

4 0

3 years ago

How did Albert Einstein come up with 3 = mc square pls help

inysia [295]

Answer: He came up with this by using theories like the photoelectric effect, the second offered experimental proof of the existence of atoms, and the third introduced the theory of special relativity.

Explanation: He was explaing the realationship between energy and mass.

Me: Hope this helps!!! May I have brainlist!?

4 0

3 years ago