Answer:
The answer is 6z-28
Step-by-step explanation:
20 - 3[4(z+1) - 6(z-2)]
= 20 - 3(4z+4-6z+12)
= 20 - 3(16 - 2z)
= 20 - 48 + 6z
= 6z - 28
Answer:
11:52...
Step-by-step explanation:
11:52. It could be any time except the time 11:37 from now, since its NOT going to be.
Hope this helps!
Answer:
Step-by-step explanation:
hello :
(x-4)²(x+3)² = -1
means : ((x-4)(x+3))² = - 1 this equation has no solutions in R
because for all x in R : ((x-4)(x+3))² ≥ 0
Short Answer B
Remark
You need not do any calculations to get the answer. You are required just to read the graph. Doing the calculations would be beneficial but unnecessary.
Step One
Find the x value.
1. If you have a ruler or a straight edge of some kind, put it on the cross point of the two graphs.
2. Make the ruler go straight up and down. You will find out it goes 1 point back of the 5.
3. Count the number of squares from 0,0 or when y = 0.
4. You will find you have to count 4 squares along the x axis.
The x value is 4.
Step Two
1. Put the ruler on the cross point again. This time make it go straight across.
2. Count up from (0,0)
You should get 8.
The y value is 8
Answer: (4,8)
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.
Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:
The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.
Thus, the lowest score of test A is given by 40(21) + 50 = 890
Therefore, the lowest score of test A is 890.
Part B:
The mean score is a measure of location, so both
addition and multiplying the mean score of test B by 40 and adding 50
to the result will affect the lowest score of test A.
Thus, the mean score of test A is given by 40(29) + 50 = 1,210
Therefore, the mean score of test A is 890.
Part C:
The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50
to the result will not affect the standard deviation of test A.
Thus, the standard deviation of test A is given by 40(2) = 80
Therefore, the standard deviation of test A is 80.
Part D
The Q3 score is a measure of location, so both
addition and multiplying the Q3 score of test B by 40 and adding 50
to the result will affect the Q3 score of test A.
Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170
Therefore, the Q3 score of test a is 1,170.
Part E:
The median score is a measure of location, so both
addition and multiplying the median score of test B by 40 and adding 50
to the result will affect the median score of test A.
Thus, the median score of test A is given by 40(26) + 50 = 1,090
Therefore, the median score of test A is 1,090.
Part F:
The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50
to the result will not affect the IQR of test A.
Thus, the IQR of test A is given by 40(6) = 240
Therefore, the IQR of test A is 240.
