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FinnZ [79.3K]
3 years ago
9

Two pay as you go which company offered the best deal

Mathematics
1 answer:
artcher [175]3 years ago
8 0

Crakberry.com

and

Uswitch.com


I hope that's help !

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Solve x2 = 12x - 15 by completing the square. Which is the solution set of the equation?
Novosadov [1.4K]

Answer:

(6-√21,  6+√21)

Step-by-step explanation:

x^2 - 12x = -15

(x - 6)^2 - 36 = -15

(x - 6)^2 = 21

x - 6 = ± √21

x = 6  ± √21

8 0
3 years ago
Simplify the following
Nostrana [21]
It a or b that my answer
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For consumers making purchases online, 60% have devices made by Apple, 85% own a smartphone, and 75% use Venmo. Also, out of the
kompoz [17]

Answer:

The probability that a customer selected at random has an Apple device or own a smartphone or both is 0.94

Step-by-step explanation:

The percentage of costumers that have a device made by Apple = 60%

The percentage of customers that own a smartphone = 85%

The percentage of customers that use Venmo = 80%

The percentage out of the smartphone users that use Venmo = 80%

The probability both independent events A and B occurring = P(A) × P(B)

The exclusive probability of A or B occurring P(A XOR B) = P(A) + P(B) - 2 × P(A ∩ B)

Therefore, the probability of A or B or both occurring is given as follows;

P(A or B or Both) = P(A) + P(B) - 2 × P(A ∩ B) + P(A) × P(B)

Where A represent the percentage of costumers that have a device made by Apple and let B represent the percentage of users that have a smartphone, we have;

P(A or B or Both) = 0.6 + 0.85 - 2×0.6×0.85 + 0.6 × 0.85 = 0.94

Therefore, the probability that a customer selected at random has an Apple device or own a smartphone (or both), P(A or B or Both) = 0.94

5 0
3 years ago
22x – 54 + 5.736x^4 - 2x^2<br> Standard form
Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

4 0
2 years ago
Select the correct answer(s) from the given options:
Olegator [25]

Answer:

A

Step-by-step explanation:

All you have to is multiply 5x20 = 100 and 5 x 10 = 50 Then add and you get 150.

5 0
3 years ago
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