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spayn [35]
3 years ago
15

Dalton proposed the first atomic model. Which of these statements accurately reflected his thinking at that time?. . . . A.. Ato

ms are all alike.. . . B.. Atoms are solid balls.. . . C.. Smaller particles are found inside atoms.. . . D.. Atoms can be divided into smaller parts.
Physics
2 answers:
IrinaK [193]3 years ago
5 0
A. Atoms are all alike

Reason: 

<span>Atoms of a given element are identical in size, mass, and other properties; atoms of different elements differ in size, mass, and other properties.</span>
QveST [7]3 years ago
4 0
A.. Atoms are alike...
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Greeley [361]
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6 0
3 years ago
When a star goes from the main sequence to the red giant phase, it becomes larger rather than smaller. This is true because grav
GuDViN [60]
I believe this is electron degeneracy, because the star is essentially having too many reactions too fast and collapses in on itself eventually.
4 0
3 years ago
A Carnot engine whose high-temperature reservoir is at 464 K has an efficiency of 25.0%. By how much should the temperature of t
nexus9112 [7]

Answer

given,

high temperature reservoir (T_c)= 464 K

efficiency  of reservoir (ε)= 25 %

temperature to decrease = ?

increase in efficiency = 42 %

now, using equation

 \epsilon = 1 - \dfrac{T_C}{T_H}

 0.25 = 1 - \dfrac{T_C}{464}

 T_C= (1 - 0.25) \times 464

 T_C= 0.75 \times 464

      T_C = 348 K

now,

if the efficiency is equal to 42$ = 0.42

 T_C= (1 - 0.42) \times 464

 T_C= 0.58 \times 464

 T_C= 269.12\ K

8 0
3 years ago
What is tan -1 (0.52)?
leva [86]

Answer:

-0.80985201682

Explanation:

Couldn't you have used Google???

7 0
3 years ago
An 87.6 g lead ball is dropped from rest from a height of 7.00 m. The collision between the ball and the ground is totally inela
bija089 [108]

Taking specific heat of lead as 0.128 J/gK = c

We have energy of ball at 7.00 meter height = mgh = 87.6*10^{-3}*9.81*7

When leads gets heated by a temperature ΔT energy needed = mcΔT

                                                                      = 87.6*10^{-3}*0.128*10^3ΔT

Comparing both the equations

                      87.6*10^{-3}*9.81*7 = 87.6*10^{-3}*0.128*10^3ΔT

                        ΔT = 0.536 K

                        Change in temperature same in degree and kelvin scale

                                      So ΔT = 0.536 ^0C

7 0
3 years ago
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