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natta225 [31]
3 years ago
14

If the speed of light in a vaccum is c, the speed of light in a medium like glass with an index of refraction of 1.5 is : (a) 3c

/2 (b) 3c (c) 2c/3 (d) 9c/4 (e) 4c/9 Please explain in detail why it is the answer you have chosen
Physics
1 answer:
maw [93]3 years ago
7 0

Answer:

The speed of light in the medium is \dfrac{2c}{3}

(c) correct option.

Explanation:

Given that,

Speed of light in vacuum = c

Refraction index = 1.5

We need to calculate the value of speed of light in the medium

The refractive index is equal to the speed of light in vacuum divide by the speed of light in medium.

Using formula of refractive index

\mu = \dfrac{c}{v}

v=\dfrac{c}{\mu}

Where, c = speed of light in vacuum

v = speed of light in medium

Put the value into the formula

v=\dfrac{c}{1.5}

v=\dfrac{2c}{3}

Hence, The speed of light in the medium is \dfrac{2c}{3}

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3 years ago
A car drives around a curve with radius 539 m at a speed of 32.0 m/s. The road is banked at 5.00°. The mass of the car is 1.40 ×
HACTEHA [7]

Answer:

f_r = 150.47 N

Explanation:

given,

r = 539 m

v = 32 m/s

road banked at = 5°

∑ F_x

\dfrac{mv^2}{r}= N sin \theta + f_r cos \theta

∑ F_y = 0

0 = N cos \theta - f_r sin \theta - mg

N = \dfrac{f_rsin \theta + mg}{cos \theta}

\dfrac{mv^2}{r}= (\dfrac{f_rsin \theta + mg}{cos \theta})sin \theta + f_r cos \theta

              = f_r sin \theta tan \theta + mg tan \theta + f_r cos \theta

        f_r = \dfrac{\dfrac{mv^2}{r}- mg tan\theta}{sin\theta tan \theta + cos \theta}

         f_r = \dfrac{\dfrac{1.4\times 10^3 \times 32^2}{539}- 1.4\times 10^{3}\times 9.8 \times 0.087}{0.087 \times 0.087 + 0.996}

f_r = 150.47 N

8 0
3 years ago
Which physical phenomena is responsible for the earth’s sky appearing blue? scattering reflection dispersion refraction
klio [65]

Answer:  Scattering reflection

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Explanation:

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Answer:

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Explanation:

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