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natta225 [31]
3 years ago
14

If the speed of light in a vaccum is c, the speed of light in a medium like glass with an index of refraction of 1.5 is : (a) 3c

/2 (b) 3c (c) 2c/3 (d) 9c/4 (e) 4c/9 Please explain in detail why it is the answer you have chosen
Physics
1 answer:
maw [93]3 years ago
7 0

Answer:

The speed of light in the medium is \dfrac{2c}{3}

(c) correct option.

Explanation:

Given that,

Speed of light in vacuum = c

Refraction index = 1.5

We need to calculate the value of speed of light in the medium

The refractive index is equal to the speed of light in vacuum divide by the speed of light in medium.

Using formula of refractive index

\mu = \dfrac{c}{v}

v=\dfrac{c}{\mu}

Where, c = speed of light in vacuum

v = speed of light in medium

Put the value into the formula

v=\dfrac{c}{1.5}

v=\dfrac{2c}{3}

Hence, The speed of light in the medium is \dfrac{2c}{3}

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Answer:

Explanation:

108,000 beats per hour

613,200 hours in 70 years

108,000 times 613,200 =

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8 0
3 years ago
A laser beam of wavelength 600 nm is incident on two slits that are separated by 0.02 mm. What is the separation between adjacen
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Answer:

option D

Explanation:

given,

wavelength = 600 nm

width of separation = 0.02 mm

L = 5 m

for mth order maxima

d \times \dfrac{y_m}{L}=m\lambda

for (m+1)th order maxima

d \times \dfrac{y_{m+1}}{L}=(m+1)\lambda

now,

y_m=\dfrac{mL\lambda}{d}      and

y_{m+1}=\dfrac{(m+1)L\lambda}{d}

hence,

\Delta y = y_{m+1} - y_m

\Delta y =\dfrac{L\lambda}{d}

\Delta y =\dfrac{5 \times 600 \times 10^{-9}}{0.02 \times 10^{-3}}

\Delta y =0.15\ m

\Delta y =15\ cm

hence, the correct answer is option D

4 0
4 years ago
A circut contains a 2 microfarads and a 20 microfarads capacitor connected in parallel. What is the total capacitance of the cir
garik1379 [7]
The answer to this question would be:C. 22mf

In this question, there are two capacitors that connected in parallel. The formula to count the capacitor is the opposite of the formula used for the resistor. If constructed in series, the capacitor will have reduced capacitance. For parallel condition the equation would be:

Ctotal= C1+C2
C total= 2 mf+ 20mf= 22mf
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4 years ago
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Answer:

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