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Anastaziya [24]
3 years ago
14

An 87.6 g lead ball is dropped from rest from a height of 7.00 m. The collision between the ball and the ground is totally inela

stic. Assuming all the ball's kinetic energy goes into heating the ball, find its change in temperature.
Physics
1 answer:
bija089 [108]3 years ago
7 0

Taking specific heat of lead as 0.128 J/gK = c

We have energy of ball at 7.00 meter height = mgh = 87.6*10^{-3}*9.81*7

When leads gets heated by a temperature ΔT energy needed = mcΔT

                                                                      = 87.6*10^{-3}*0.128*10^3ΔT

Comparing both the equations

                      87.6*10^{-3}*9.81*7 = 87.6*10^{-3}*0.128*10^3ΔT

                        ΔT = 0.536 K

                        Change in temperature same in degree and kelvin scale

                                      So ΔT = 0.536 ^0C

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Explanation:

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==================================================================

Time

Use formula:

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Everything inside the root is solved first. So, we solve the multiplication of the numerator:

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==================================================================

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use formula:

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Replace:

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Multiply:

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==================================================================

How long does it take to reach the ground?

Takes time to reach the ground in <u>2.01 seconds.</u>

How fast does it hit the ground?

Hits the ground with a speed of <u>19.7 meters per seconds.</u>

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