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nalin [4]
3 years ago
12

Will name brainliest please pleas answer

Physics
1 answer:
Greeley [361]3 years ago
6 0
3 is the answer teeeeeeeeeheeeeeeeee
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Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic
Elena-2011 [213]

Answer:

Answer:

1.1 x 10^9 ohm metre

Explanation:

diameter = 1.5 mm

length, l = 5 cm

Potential difference, V = 9 V

current, i = 230 micro Ampere = 230 x 10^-6 A

radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m

Let the resistivity is ρ.

Area of crossection

A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2

Use Ohm's law to find the value of resistance

V =  i x R

9 = 230 x 10^-6 x R

R = 39130.4 ohm

Use the formula for the resistance

R=\rho \frac{l}{A}

\rho =\frac{RA}{l}

\rho =\frac{39130.4\times 0.05}{1.766\times 10^{-6}}

ρ = 1.1 x 10^9 ohm metre

Explanation:

7 0
3 years ago
A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.883 s. How much time
Salsk061 [2.6K]

Answer:

1.25 s

Explanation:

We are given that

Initial velocity of boy=u=0

Time=0.883 s

Let x be the total distance covered by boy in entire trip.

s=\frac{x}{2}

We know that

s=ut+\frac{1}{2}gt^2

Where g=10m/s^2

Substitute the values

\frac{x}{2}=0\times 0.883+\frac{1}{2}(10)(0.883)^2

\frac{x}{2}=3.898

x=3.898\times 2=7.796m

Again using the above formula

7.796=0(t)+\frac{1}{2}(10)t^2

7.796=5t^2

t^2=\frac{7.796}{5}=1.5592

t=\sqrt{1.5592}=1.25 s

Hence, 1.25 s passes during his entire tripe from the top down to the water.

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3 years ago
Write newtone first law
gtnhenbr [62]

Newtons first law is that an Object that is in motion will stay in motion until an unbalanced force acts upon it, and part 2 is that an object at rest will stay at rest until and unbalanced force acts upon it

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For a spring oscillating in simple harmonic motion, at what point will the velocity of
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Answer:

equilibrium position.

Explanation:

In simple harmonic motion , velocity v(t) is given by,

v(t) = -ω A sin(ωt + φ)

where

ω = angular velocity of the corresponding circular motion

A = amplitude

t = time

φ = the initial angle of the corresponding circular motion when the motion begin.

v (t) get maximized when sin value is maximized , i.e. sin \alpha=1

The particle has maximum speed when it passes through the equilibrium position.

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During test-out procedures, a 239Pu-fueled thermal reactor is operated for a time at a power of 1 megawatt.The power is then to
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