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Dmitriy789 [7]
2 years ago
6

What were two reasons that the Krystal Beslanowitch case was finally closed?

Physics
1 answer:
lesantik [10]2 years ago
7 0

Answer:

1. Police Weren't Able To Find Any Real Leads

2. They Didn't Find Any Clues To The Killer Until 18 Years Later

Explanation:

It was unknown at the time, but it would go on to take 18 years for her killer to be arrested and tried for her death. The initial case went on from 1995 to 1997 but ended up closing when the police department was unable to find any real leads.

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A seasoned mini golfer is trying to make par on a tricky number five hole. The golfer can complete the hole by hitting the ball
liberstina [14]

Answer:5.17 m/s

Explanation:

Given

let u be the speed at cliff initial point

range over cliff is 1.45 m

and range of projectile is given by

R=\frac{u^2\sin 2\theta }{g}

1.45=\frac{u^2\sin 90}{9.8}

u=3.77 m/s

Conserving Energy

E_{bottom}=E_{initial\ point\ at\ cliff}

Kinetic energy=Kinetic energy +Potential energy gained

Let v be the initial velocity

\frac{mv^2}{2}=mgh+\frac{mu^2}{2}

v^2=u^2+2gh

v=\sqrt{u^2+2gh}

v=\sqrt{3.77^2+2\time 9.8\times 0.64}

v=\sqrt{26.75}=5.17 m/s

5 0
3 years ago
Two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 221
8_murik_8 [283]

Answer:

v = 8.8 m /s

Explanation:

For listener and source going away from each other the formula of Doppler effect is as follows

\frac{f}{f_0} = \frac{V-v}{V+v}

V is velocity of sound , v is velocity of listner and source of sound

f₀ is apparent frequency and f is real frequency

V = 343 , v = ? ,f = 210 , f₀ = 221

Put these value in the relation above

[tex]\frac{210}{221} = \frac{343-v}{343+v}[/tex]

v = 8.8 m /s

6 0
3 years ago
You throw a rock up into the air as hard as you can. It stays in the air a total of 6.0 s. What
vaieri [72.5K]

Answer:

<h2>5.9 x 10</h2>

Explanation:

6 0
2 years ago
What are the opposite ends of a magnet called? A. north and south terminals B. north and south poles C. magnetic fields D. magne
Bezzdna [24]

I think the answer is B.

Hope this helps.

6 0
3 years ago
Read 2 more answers
An organ pipe open at both ends has a length of 0.80 m. If the velocity of sound in air is 340 m/s, what is the frequency of the
bazaltina [42]

Answer:

the frequency of the second harmonic of the pipe is 425 Hz

Explanation:

Given;

length of the open pipe, L = 0.8 m

velocity of sound, v = 340 m/s

The wavelength of the second harmonic is calculated as follows;

L = A ---> N   +  N--->N   +   N--->A

where;

L is the length of the pipe in the second harmonic

A represents antinode of the wave

N represents the node of the wave

L = \frac{\lambda}{4} + \frac{\lambda}{2} + \frac{\lambda}{4} \\\\L = \lambda

The frequency is calculated as follows;

F_1 = \frac{V}{\lambda} = \frac{340}{0.8} = 425 \ Hz

Therefore, the frequency of the second harmonic of the pipe is 425 Hz.

5 0
3 years ago
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