Answer:the hose would explode and you would mess the water system out
Explanation:
Answer:
a. the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon
Explanation:
F= ma
v²=u² -2aS
(1.56 ✕ 10⁶)²=(2.40 ✕ 10⁶)²-2a(1220)
a=1.36×10⁹m/s²
recall
F=ma
F = 1.88 ✕ 10⁻²⁸ kg × 1.36×10⁹m/s²
F= 2.55 × 10⁻¹⁹N
the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon
F/mg= 2.55 × 10⁻¹⁹/ (1.88 ✕ 10⁻²⁸ × 9.8)
= 1.38 × 10⁸
Because gases flow easily. A hot batch of gas can rise through
the surrounding gas a lot easier than, say, a hot batch of mud can
rise through the surrounding mud.
Your answer would be 94. This is because only 10 transfers, so 90 is lost from the mouse. It takes 4 for the cat to pounce. When you add 90 and 4 you get your answer.....94
Answer:
The mass of the box, m = 30.61 Kg
The acceleration of the box, a = 0.65 m/s²
Explanation:
Given that,
The weight of the box, w = 300 N
The sliding force acting on the box, F = 20
Since the weight of a body is equal to the product of mass and displacement. The mass of the box is given by the relation
m = w/g
Substituting the given values in the above equation
m = 300 / 9.8
= 30.81 Kg
Hence, the weight of the box is, w = 30.81 Kg
Since the sliding force acting on the box is 20 N
Therefore, acceleration
a = F / m
= 20 / 0.81
= 0.65 m/s²
Hence, the acceleration acting on the box, a = 0.65 m/s²