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nydimaria [60]
3 years ago
14

First, water evaporates from the ocean to the atmosphere, then ____________. put each step in the correct order.

Physics
1 answer:
oksian1 [2.3K]3 years ago
3 0
<span>First, water evaporates from the ocean to the atmosphere, then... put each step in the correct order.
</span>Second- atmospheric circulation advects the water.
Third- water condensates to form clouds.
Fourth- precipitation falls from clouds to the land.
Fifth- some water stored as snow or ice.
Sixth- water either ±ows along the surface in rivers and lakes or infiltrates the ground.
Seventh- water returns to the ocean.
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2 years ago
Diamond and graphite are both composed entirely of carbon yet graphite is soft and diamond is one of the hardest substances know
pogonyaev

Explanation:

This difference is because of the difference in arrangement of carbon atoms both graphite and Diamond.

Carbon atoms in graphite are arranged in layered form in an infinite array of layers. These layers are held together by a weaker force of attraction called vander waal's force of attraction such that layer's can slip over one another. Whereas in diamond carbon atoms are arranged tetrahedrally. Each carbon atom is attached to four carbon atoms with a bond angle of 109.5°. It is strong rigid three dimensional structure that results in infinite array atoms. This accounts for hardness of the diamond.

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3 years ago
The elements that do not ordinarily form compounds are
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The noble gasses, they are the elements on group 18 of the periodic table and do not usually form compounds. The noble gases are as follows: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og).

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8 0
3 years ago
Read 2 more answers
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7 0
2 years ago
A proton and an electron are both accelerated to the same final speed. If λp s the de Broglie wavelength of the proton and e is
meriva

Answer:

Explanation:

The relation between the de Broglie wavelength and the momentum of the particle is given by

\lambda =\frac{h}{m\times v}

where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.  

So, the de broglie wavelength of proton is given by

\lambda _{p}=\frac{h}{m_{p}\times v} .... (1)

The de broglie wavelength of electron is given by

\lambda _{e}=\frac{h}{m_{e}\times v} .... (2)

Divide equation (2) by equation (1), we get

\frac{\lambda _{e}}{\lambda _{p}}=\frac{m_{p}}{m_{e}}

As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.

5 0
3 years ago
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