5 and 4 digit only Po that's the answers
Simply going to factorise this:
v(v - 1) -2(1 - v):
Note 1 - v = -(v-1)
<span>v(v - 1) -2(1 - v)
</span>
<span>v(v - 1) -2(-(v - 1))
</span>
<span>v(v - 1) +2(v - 1)</span>
(v + 2)(v - 1)
<h3>
Answer: 10,080</h3>
Explanation:
There are 8 letters so there are 8! = 8*7*6*5*4*3*2*1 = 40,320 permutations of those letters. However, the letters "O" and "L" show up twice each, so we must divide by 2! = 2*1 = 2 for each instance this happens.
So,
(8!)/(2!*2!) = (40,320)/(2*2) = (40,320)/4 = 10,080
is the number of ways to arrange the letters of "football".
The reason we divide by 2 for each instance of a duplicate letter is because we can't tell the difference between the two "O"s or the two "L"s. If there was a way to distinguish between them, then we wouldnt have to divide by 2.
The third one Hope this helps ur welcome
