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Alex Ar [27]
3 years ago
8

In stars, hydrogen nuclei combine with each other to form helium and other heavier elements. what is this process called?

Chemistry
1 answer:
slega [8]3 years ago
6 0
Hello!

The process in which hydrogen nuclei combine with each other to form helium and other heavier elements is called Nuclear Fusion.

Nuclear Fusion happens when the repulsion between the two nuclei is overcome by the Strong Interaction Force, spending and releasing high amounts of energy.

The two nuclei need to be close enough for Nuclear Fusion to happen, and the energy needed to achieve that is given by the extremely hot temperatures that exist within stars (about 15 000 000 Kelvin). That's why this kind of reactions are common in stars. 

Have a nice day!

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Which of the following lists the elements in order of increasing malleability?
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The answer would be (B) Sb, Sn, Se.

The periodic table may look like a confusing checkerboard of elements, but they are categorized in more ways than you may know.

For malleability, we look for metals. Metals/metallic elements have characteristics like electrical conductivity, <u>malleability</u>, ductility, and other physical characteristics like luster. The more an element is metallic, the more of these characteristics it will have.

So to answer this question, you simply have to see what kind of elements these are:

Sb, 51 (Antimony): <em>Metalloid</em>

Sn, 50 (Tin): <em>Transition Metal</em>

Se, 34 (Selenium): <em>Non-Metal</em>

Therefore, Antimony will have more metal characteristics than the rest, putting it at the top. Selenium is a non-metal, so that goes at the bottom, and Tin will be second.

4 0
4 years ago
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2L of hydrogen has an initial pressure of 750 mmHg, what is the final pressure in mmHg if the volume increases to 20 L with a co
Verdich [7]

Answer: The final pressure is 75 mm Hg.

Explanation:

According to Boyle's law, at constant temperature the pressure of a gas in inversely proportional to volume.

Since, it is given that the temperature is constant. Hence, formula used is as follows.

P_{1}V_{1} = P_{2}V_{2}

Substitute the values into above formula as follows.

P_{1}V_{1} = P_{2}V_{2}\\750 mm Hg \times 2 L = P_{2} \times 20 L\\P_{2} = \frac{750 mm Hg \times 2 L}{20 L}\\= 75 mm Hg

Thus, we can conclude that the final pressure is 75 mm Hg.

3 0
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Which practice does the Montreal Protocol aim to reduce?
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3 years ago
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A volume of 129 mL of hydrogen is collected over water. The water level in the collecting vessel is the same as the outside leve
mixas84 [53]

Explanation:

As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.

So, using ideal gas equation we will calculate the number of moles as follows.

                  PV = nRT

or,           n = \frac{PV}{RT}

                 = \frac{\frac{756}{760}atm \times 0.129 L}{0.0821 Latm/mol K \times 298 K}

                  = 0.0052 mol

Also,  No. of moles = \frac{mass}{\text{molar mass}}

               0.0052 mol = \frac{mass}{2 g/mol}

                  mass = 0.0104 g

As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at 25^{o}C

                P_{\text{water vapor}} = 24 mm Hg

                                = \frac{24}{760} atm

                                = 0.03158 atm

Now,   P = \frac{756}{760} - 0.03158

              = 0.963 atm

Hence,   n = \frac{0.963 atm \times 0.129 L}{0.0821 L atm/mol K \times 298 K}

                 = 0.0056 mol

So, mass of H_{2} = 0.0056 mol × 2

                         = 0.01013 g (actual yield)

Therefore, calculate the percentage yield as follows.

      Percent yield = \frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100

                              = \frac{0.01013 g}{0.0104 g} \times 100            

                              = 97.49%

Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.

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The scientific method typically ends with a ​
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Answer: Conclusion

Explanation:

After they test the hypothesis they come to a conclusion of the answer.

and sometime test it again and again

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