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3 years ago

Write the chemical equation for fot the reaction between mgcl2 and the soap you preapred

1 answer:

5 0

Soap is the sodium or potassium salt of long chain of fatty acid. Fatty acids when treated with NaOH or KOH forms Soap. This process is called as Saponification. Examples of Soap are as follow,

1. Sodium Stearate C₁₇H₃₅COONa

2. Potassium Oleate C₁₇H₃₃COOK

Reaction of Soap with MgCl₂;

When Soap is treated with MgCl₂ or CaCl₂ it forms insoluble precipitate called S.C.U.M. The reactions with MgCl₂ are as follow,

2C₁₇H₃₅COONa + MgCl₂ --------> 2C₁₇H₃₅COOMg + 2 NaCl

2C₁₇H₃₃COOK + MgCl₂ --------> 2C₁₇H₃₅COOMg + 2 KCl

These reaction are often found in hard water. And this reaction decreases the effectiveness of soap.

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0 ml of pure water at 282 k is mixed with 50.0 ml of pure water at 343 k. what is the final temperature of the mixture?

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assuming oxygen behaves like an ideal gas, what volume in liters would 3.50 moles of oxygen gas occupy at STP?

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78.4L

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3 years ago

0.12g of rock salt was dissolved in water and titrated with 0.1moldm^-3 silver nitrate until the first permanent brown precipita

AysviL [449]

moles Cl⁻ : 0.00197

mass NaCl : 0.115

% purity : 95.83%

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

mol Cl⁻

Reaction

Molarity(concentration) of AgNO₃ = 0.1 mol/dm³(L) = 0.1 M

Volume=V of AgNO₃ = 19.7 ml(cm³)

so mol of AgNO₃ :

$\tt mol=M\times V\\\\mol=0.1~mol/L\times 0.0197~L\\\\mol=0.00197$ .

From the equation, mol ratio AgNO₃ : NaCl = 1 ; 1, so mol NaCl= mol AgNO₃= 0.00197

NaCl⇒Na⁺+Cl⁻

mol Cl⁻ : mol NaCl = 1 : 1, mol Cl⁻ = 0.00197

mass NaCl (MW=58.5 g/mol) :

$\tt mass=mol\times MW\\\\mass= 0.00197\times 58.5=0.115~g$

% purity :

$\tt \%purity=\dfrac{mass~NaCl}{mass~rock}\times 100\%\\\\\%purity=\dfrac{0.115}{0.12}\times 100\%=95.83\%$

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3 years ago