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Jet001 [13]
3 years ago
15

How much more acidic is a person’s blood if it has a pH of 7.3 compared to its preferred 7.4? How much more alkaline is a person

’s blood if it has a pH of 7.6 rather than its preferred 7.4?
Chemistry
1 answer:
enot [183]3 years ago
4 0

Answer:

0.1 and 0.2.

Explanation:

The person's blood is 0.1 decreases and become more acidic if it has a pH of 7.3 compared to its preferred 7.4 while on the other hand, the person's blood is 0.2 increases and become more alkaline it has a pH of 7.6rather than its preferred 7.4. There is 0.1 decrease and 0.2 increase in the pH of the person's blood. If the pH decreases so it means it moves towards more acidic whereas, if the pH increases there is moves towards alkaline.

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dolphi86 [110]

Here we have explain that the maximum possible electrons present in nitrogen valence shell is 8 whereas in phosphorous 12 valence electrons are present.

Although both nitrogen (N) and phosphorous (P) belongs to the same series there are several properties which are different between both the element. The number of electrons present in nitrogen is seven which are present in the -s and -p orbitals. The electronic configuration of nitrogen is 1s²2s²2p³. In which the outermost electrons are the valence electrons i.e. 5 valence electrons are present. The maximum orbitals are possible under the principal quantum number 2 are -s and -p orbitals. Now the maximum capacity of the p orbital to contain 6 electrons, as it is half filled in nitrogen another 3 electrons can be incorporated. Thus the maximum number of electrons can be present in nitrogen is 10 among which 8 is the valence electrons.

On the other hand there are 15 electrons in phosphorous the electronic configuration is 1s²2s²2p⁶3s²3p³. Now the principal quantum number 3 can have three orbitals -s, -p and -d. So another 13 electrons can be incorporated (3 in -p orbital and 10 in -d orbital) among which upto 12 electrons can be its valence electrons.

8 0
3 years ago
Question 3 (1 point) The extinction coefficient for copper sulfate in aqueous solution is 12 M-1.cm-1 at 800 nm. If the absorban
Troyanec [42]

Answer:

The concentration of the copper sulfate solution is 83 mM.

Explanation:

The absorbance of a copper sulfate solution can be calculated using Beer-Lambert Law:

A = ε . c . <em>l</em>

where

ε is the extinction coefficient of copper sulfate (ε = 12 M⁻¹.cm⁻¹)

c is its molar concentration (what we are looking for)

l is the pathlength (0.50 cm)

We can use this expression to find the molarity of this solution:

c=\frac{A}{\epsilon.l } =\frac{0.5}{12M^{-1}cm^{-1}0.50cm  } =0.083M=83mM

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