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Softa [21]
3 years ago
11

True or false: BrF5(aq) is a good insulator.

Chemistry
1 answer:
jeka943 years ago
7 0

Answer:

true

hope this helps :)

Explanation:

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The removal of one or more electrons from a neutral atom results in and
Studentka2010 [4]

Answer:

The removal of one or more electrons from a neutral atom results in a cation.

Explanation:

When you remove electrons from a neutral atom, the atom becomes more positive. Electrons have a negative charge and the protons inside of the nucleus have a positive charge. When electrons are removed, the positive charges from the protons outweigh the negative charges. This results in a positively charged atom, called a cation.

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1 year ago
mr. Rose asked his student to draw a quadrilateral with four unequal sides. An example of this kind of quadrilateral
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You are a researcher with an interest in understanding the mechanism of serine protease enzymes. To test the effect of the role
yawa3891 [41]
Ngl didn’t read it so I’m not gonna answer it. Don’t report please just want to ask a question but have to answer two
5 0
3 years ago
Consider the balanced reaction
VARVARA [1.3K]

The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

<h3>What is the use of aluminium chloride ?</h3>

Aluminum chloride is useful for the treatment of palmar, plantar, and axillary hyperhidrosis.

Aluminum chloride has also been reported to be useful in facial and scalp hyperhidrosis

The balanced chemical equation represents the mole ratio in which the chemicals combine.

In this case, illustrates that 2 mol Al produces 2 mol Al Cl₃, hence these 2 chemicals are in a 1:1 ratio.

Thus, to produce 8.70 mol aluminium chloride, it will require 8.70 mol aluminium.

But this quantity of Al has a mass in grams of

m = n × Mr

   = 8.70 mol × 27g/mol

   = 234.9 g

Hence, The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g

Learn more about mole concept here ;

https://brainly.in/question/12599804

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4 0
1 year ago
Two trials are run, using excess water. In the first trial, 7.8 g of Na2O2(s) (molar mass 78 g/mol) is mixed with 3.2 g of S(s).
Tema [17]

Answer:

The answer is "Option C".

Explanation:

Given equation:

2Na_20_2 (s)+S(s)+2H_2O \longrightarrow  4NaOH(aq)+SO_2(aq)

\to \Delta H^{\circ}_{rxn} (298\ K) = -610 \frac{kJ}{mol}

\to Na_2O_2  \ Mass = 7.8 \ g\\\\ \to  Na_2O_2 \ Molar \ mass = 78 \frac{g}{mol}

Na_2O_2 Has been the reactant which is limited since the two experiments are equal toNa_2O_2 for relationship between stress amounts.

Na_2O_2, n =\frac{Mass of Na_2O_2}{Molar mass of Na_2 O_2}=\frac{7.8 \ g}{78 \frac{g}{mol}} =0.1 \ mol \\\\q=\Delta H^{\circ}_{rxn} \times n = \frac{ -610 \ kJ}{ 2 \ mol \ Na_2 O_2} \times 0.1 \ mol  \ Na_2O_2= 30.5 \ KJ\\\\

Limiting reactant =Na_2O_2

q=30.5 \ kJ \approx 30 \ kJ

8 0
3 years ago
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