Brian is solving the equation x^2 - 3/4x= 5. What value must be added to both sides of the equation to make the left side a perf
ect-square trinomial?
2 answers:
<span>((-3/4)/2)^2 = 9/64 I HOPE THIS HELP</span>
X^2 - 3/4 x = 5
-3/4 / 2 = -3/8 so its
x^2 - 3/4x + 3/8^2 = 5 + 3/8^2
(x - 3/8)^2 = 5 + 9/64
The answer is 9/64
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