Explanation:
It is given that,
An electron is released from rest in a weak electric field of, 
Vertical distance covered, 
We need to find the speed of the electron. Let its speed is v. Using third equation of motion as :

.............(1)
Electric force is
and force of gravity is
. As both forces are acting in downward direction. So, total force is:



Acceleration of the electron, 


Put the value of a in equation (1) as :


v = 0.010 m/s
So, the speed of the electron is 0.010 m/s. Hence, this is the required solution.
Answer:
Final velocity, V = 11.5m/s
Explanation:
Given the following data;
Initial velocity, U = 2.5m/s
Acceleration, a = 1.5m/s²
Time, t = 6secs
To find the final velocity, we would use the first equation of motion
V = U + at
Substituting into the equation, we have
V = 2.5 + 1.5*6
V = 2.5 + 9
Final velocity, V = 11.5m/s
The number of protons an element has is its atomic number so the atomic number would be 29
Answer:
1.29649
488.08706 nm

231715700.28346 m/s
Explanation:
n denotes refractive index
1 denotes air
2 denotes solution
= 632.8 nm
From Snell's law we have the relation

Refractive index of the solution is 1.29649
Wavelength is given by

The wavelength of the solution is 488.08706 nm
Frequency is given by

The frequency is 

The speed in the solution is 231715700.28346 m/s
Answer: D. Albedo
Explanation:
The proportion of total light incident on surface that is reflected back is called its albedo. These are typical features of an astronomical body. It is a dimension less quantity and its value ranges from 0 to 1. Light surfaces reflect larger amount of light than dark surfaces. This feature can be clearly seen on planet Mars and the Moon.
Thus, the fraction of the total radiation that is reflected by any surface is called its <u>Albedo.</u>