A system consists of two particles. Which of the following scenarios would the force on each particle increase the most? If mult
1 answer:
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Answer:
Explanation:
The weight of the box is
W = 253.1N
Weight is on an incline plane
θ = 39.7°
The weight of an object is always acting downward
So, the weight makes an angle of 39.7° with the vertical component
Then, it's horizontal component is
Wx = W•Sinθ
Wx = 253.1 × Sin 39.7°
Wx = 161.67 N
The horizontal component of the weight is 161.67N
This is the force acting down the plane.
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Answer:
The spring constant of this spring is 200 N/m.
Explanation:
Given:
Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]
Stretched length of the spring (x₁) = 18 cm = 0.18 cm
Force acting on the spring (F) = 16 N
Spring constant of the spring (k) = ?
First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.
So, Change in length = Final length - Initial length
Now, restoring force acting on the spring is directly related to its elongation or compression as:
Rewriting in terms of 'k', we get:
Now, plug in the given values and solve for 'k'. This gives,
Therefore, the spring constant of this spring is 200 N/m.