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IrinaK [193]
3 years ago
7

A system consists of two particles. Which of the following scenarios would the force on each particle increase the most? If mult

iple scenarios would increase it by the same amount, select all that apply.
Group of answer choices

Doubling the distance between the particles.

Halving the distance between the particles.

Doubling one charge.

Doubling both charges

Doubling one charge, halving the other.

Halving one charge.

halving both charges.
Physics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

c

Explanation:

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Answer:

gravity

Explanation:

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3 years ago
how to A golf ball of mass 0.045 kg is hit off the tee at a speed of 45 m/s. The golf club was in contact with the ball for 3.5
Alexandra [31]

Answer: a) 12857.1 m/s/s b) 578.6 N

Explanation:

Impulse = change in momentum

Ft = mV2 - mV1

V = AT, 45 / .0035 = 12857.1 m/s/s

(b) .045 x 12857.1 = 578.6 N

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Tina drove 3 miles north and 4 miles west to get to her grandmother’s house. Find the distance and displacement.​
TEA [102]

Answer:

distance = 3 + 4 = 7 mi

displacement is √(3² + 4²) = 5 mi

Explanation:

6 0
2 years ago
n the Bohr model of the hydrogen atom (see Section 39.3), in the lowest energy state the electron orbits the proton at a speed o
Ivahew [28]

Answer:

(a) T=1.5*10^{-6}s

(b) I=1.1*10^{-3}A

(c) \mu=9.71*10^{-24}A\cdot m^2

Explanation:

(a) The orbital period is the time that the electron spend to travel the orbit of the atom. Thus, it is given by the length of the circular orbit divided by its velocity:

T=\frac{2\pi r}{v}\\T=\frac{2\pi(5.3*10^{-11}m)}{2.2*10^{6}\frac{m}{s}}\\T=1.5*10^{-6}s

(b) Current means charge over time, So, in this case is charge over period:

I=\frac{q}{t}\\I=\frac{e}{T}\\I=\frac{1.6*10^{-19}C}{1.5*10^{-6}s}\\\\I=1.1*10^{-3}A

(c) Magnetic moment is given by:

\mu=IA

Here A is the area of the orbit.

\mu=I\pi r^2\\\mu=(1.1*10^{-3}A)\pi(5.3*10^{-11}m)^2\\\mu=9.71*10^{-24}A\cdot m^2

4 0
3 years ago
Three identical metallic conducting spheres carry the following charges: q = +3.8 μC, q = −2.6 μC, and q = −8.8 μC. The spheres
Kitty [74]

Answer:

-4.1μC is the final charge on the third sphere

Explanation:

From the given data, q1 and q2 are brought into contact as they are both conductors,  as such there will be evenly distribution of charges.

a) charge on each sphere(Q) = q1 + q2 / 2

= +3.8 μC + (- 2.6 μC) / 2 = 1.2μC/2 = 0.6μC

b) Now, one of those two spheres is brought into contact with the third sphere ; Q is brought into contact with q3 = Q + q3 / 2

= 0.6μC - 8.8 μC /2 = -8.2 μC/2

= -4.1μC is the final charge on the third sphere.

6 0
3 years ago
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