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gladu [14]
3 years ago
6

A car starts from a stopped position at a red light. At the end of 30 seconds, its speed is 20 meters per second. What is the ac

celeration of the car?
A. 1.5 m/s
B. 0.7 m/s
C. 0.7 m/s 2
NEED help please HEELLPP
Physics
1 answer:
Gnoma [55]3 years ago
5 0
A=deltav/t
Vf=20m/s
Vi=0m/s
(20-0)/30
=0.667 m/s^2
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a light wave travels at 3.0 x 10^8 m/s. if the wavelength of a red wave is 700 x 10^-9m, what is the frequency?
asambeis [7]

Frequency  =  (speed) divided by (wavelength)

                 = (3 x 10⁸ m/s)  /  (700 x 10⁻⁹ m)

                 =  (3 / 700) x 10¹⁷ ( per sec )

                 =    4.286 x 10¹⁴  per sec  =  4.286 x 10¹⁴ Hz.

                                                           =      42,860 GHz .

3 0
3 years ago
Light with a wavelength of 612 nm incident on a double slit produces a second-order maximum at an angle of 25 degree. What is th
erastova [34]

Answer:

Speration between the slits d=2.86\ \mu m

Explanation:

Given that,

Wavelength of light, \lambda=612\ nm=612\times 10^{-9}\ m

It is incident on a double slit produces a second-order maximum at an angle of 25 degree.

The condition for maxima is given as :

dsin\theta=m\lambda

d = seperation between the slits

m = order, m = 2

d=\dfrac{m\lambda}{sin\theta}

d=\dfrac{2\times 612\times 10^{-9}\ m}{sin(25)}

d = 0.00000289

or

d=2.86\mu m

So, the seperation between the silts is 2.86\ \mu m. Hence, this is the required solution.

3 0
3 years ago
An iron block of mass 10 kg rests on a wooden plane inclined at 30° to the horizontal. It is found
Kaylis [27]

I assume the 100 N force is a pulling force directed up the incline.

The net forces on the block acting parallel and perpendicular to the incline are

∑ F[para] = 100 N - F[friction] = 0

∑ F[perp] = F[normal] - mg cos(30°) = 0

The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.

Then

F[friction] = 100 N

F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N

If µ is the coefficient of static friction, then

F[friction] = µ F[normal]

⇒   µ = (100 N) / (84.9 N) ≈ 1.2

5 0
2 years ago
During a normal reaction to a stressful event, muscles are moved to their maximum capacity, and sensitivity is
Aleonysh [2.5K]

Answer:

The paper focuses on the biology of stress and resilience and their biomarkers in humans from the system science perspective. A stressor pushes the physiological system away from its baseline state toward a lower utility state. The physiological system may return toward the original state in one attractor basin but may be shifted to a state in another, lower utility attractor basin. While some physiological changes induced by stressors may benefit health, there is often a chronic wear and tear cost due to implementing changes to enable the return of the system to its baseline state and maintain itself in the high utility baseline attractor basin following repeated perturbations. This cost, also called allostatic load, is the utility reduction associated with both a change in state and with alterations in the attractor basin that affect system responses following future perturbations. This added cost can increase the time course of the return to baseline or the likelihood of moving into a different attractor basin following a perturbation. Opposite to this is the system's resilience which influences its ability to return to the high utility attractor basin following a perturbation by increasing the likelihood and/or speed of returning to the baseline state following a stressor. This review paper is a qualitative systematic review; it covers areas most relevant for moving the stress and resilience field forward from a more quantitative and neuroscientific perspective.

Explanation:

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s344n2d4d5 [400]

Answer:

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Explanation:

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pls mark me the brainliest

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