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3 years ago

How can you tell if a diamond real or fake

Physics

2 answers:

rewona [7]3 years ago

8 0

Scratch it on a peice of glass

notsponge [240]3 years ago

6 0

You can tell if a diamond is real or fake by checking its edges. Real diamonds have sharp edges, while fake ones don't. Another way is to bring it to a jewelry shop, or have a professional look at it, which is the best and easiest way. You can also see if a diamond is real or not by placing it on top of a newspaper, and to see if you can read the text through the diamond. If you can, then it is a fake, because real diamonds contort light, making the letters of the newspaper blurry.

~Hope I helped!~

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A long solenoid (diameter = 5.0 cm) is wound with 960 turns per meter of thin wire through which a current of 300 mA is maintain

Semenov [28]

Answer: The magnetic field B= 4.82×10^-4T

Explanation:

There are two sources of magnetic field; the magnetic field due to solenoid and magnetic field due to wire. Their sum will give the total magnetic field

The magnetic field due to solenoid is constant at any point while the magnetic field due to wire varies with 1/radius.

Since they are perpendicular to each other;

Using Pythagoras theorem

B^2 =(B1)^2+B2)^2

B1 is the magnetic field due to solenoid and B2 is the magnetic field due to wire

B1= (μNI1)/L

B2=μI2/2πr

Where N/L is the of turns per meter = 960m^-1

I1 is the current in the solenoid =300mA=0.3A

I2 is the current in the wire = 12A

r is the distance from the axis of solenoid = 2cm= 0.02m

μ is the magnetic constant= 4π×10^-7Tm/A

Magnetic field due to solenoid B1=(4π×10^-7×960×0.3)

B1= (3.6191×10^-4 )

Magnetic field due to wire

B2 = (4π×10^-7×12)/2π × 0.02

B2 = 1.2×10^-4

B^2 =( 3.16191×10^-4)^2 × (1.2×10^-4)^2

B=3.8×10^-4T

Therefore the magnetic field is 0.38mT

5 0

3 years ago

Someone pls answer! i will give u brainliest

olya-2409 [2.1K]

Answer:

Liquid

Explanation:

Before anything evaporates, it is in a liquid state.

4 0

3 years ago

Read 2 more answers

A 2.0 kg wood block is launched up a wooden ramp that is inclined at a 30˚ angle. The block’s initial speed is 10 m/s. What vert

WARRIOR [948]

Answer:

The wood block reaches a height of 4.249 meters above its starting point.

Explanation:

The block represents a non-conservative system, since friction between wood block and the ramp is dissipating energy. The final height that block can reach is determined by Principle of Energy Conservation and Work-Energy Theorem. Let suppose that initial height has a value of zero and please notice that maximum height reached by the block is when its speed is zero.

$\frac{1}{2}\cdot m \cdot v^{2} = m \cdot g\cdot h + \mu_{k}\cdot m\cdot g\cdot s \cdot \sin \theta$

$\frac{1}{2}\cdot v^{2} = g\cdot h + \mu_{k}\cdot g\cdot \left(\frac{h}{\sin \theta} \right)\cdot \sin \theta$

$\frac{1}{2}\cdot v^{2} = g\cdot h +\mu_{k}\cdot g\cdot h$

$\frac{1}{2}\cdot v^{2} = (1 +\mu_{k})\cdot g\cdot h$

$h = \frac{v^{2}}{2\cdot (1 + \mu_{k})\cdot g}$ (1)

Where:

$h$ - Maximum height of the wood block, in meters.

$v$ - Initial speed of the block, in meters per second.

$\mu_{k}$ - Kinetic coefficient of friction, no unit.

$g$ - Gravitational acceleration, in meters per square second.

$m$ - Mass, in kilograms.

$s$ - Distance travelled by the wood block along the wooden ramp, in meters.

$\theta$ - Inclination of the wooden ramp, in sexagesimal degrees.

If we know that $v = 10\,\frac{m}{s}$ , $\mu_{k} = 0.20$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the height reached by the block above its starting point is: