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3 years ago

How can you tell if a diamond real or fake

Physics

2 answers:

rewona [7]3 years ago

8 0

Scratch it on a peice of glass

notsponge [240]3 years ago

6 0

You can tell if a diamond is real or fake by checking its edges. Real diamonds have sharp edges, while fake ones don't. Another way is to bring it to a jewelry shop, or have a professional look at it, which is the best and easiest way. You can also see if a diamond is real or not by placing it on top of a newspaper, and to see if you can read the text through the diamond. If you can, then it is a fake, because real diamonds contort light, making the letters of the newspaper blurry.

~Hope I helped!~

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A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele

iren [92.7K]

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, $n=1.35$ .

The thickness of the soap bubble wall is, $t=300 nm$ .

Now, for constructive interference of soap bubble.

$2nt=(m+\frac{1}{2})\lambda$ .

Now for first order m=1.

Therfore,

$\lambda =\frac{4}{3} tn$

Substitute all the variables in the above equation.

$\lambda =\frac{4}{3} (1.35)(300 nm)$ .

Therefore,

$\lambda =540 nm$ .

Therefore the visible light wavelength which is strongly reflected is 540 nm.

6 0

3 years ago

If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50

dmitriy555 [2]

Answer:

This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h

24.29m/s or 87.4km/h

Explanation:

Let's find the acceleration of the car:

let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s

a = (vf-vi)/Δt

a = (16.67m/s-0)/8.0

a = 2.08m/s^2

Now we can use this acceleration to find vf in the second part:

50km/h is 13.89m/s

a = (vf-vi)Δt

vf = aΔt + vi

vf = 2.08m/s^2*5.0+13.89m/s

vf = 24.29m/s (87.4km/h)

3 0

2 years ago

If 30.45 grams of water is to be heated up 3.3 degrees to make baby

KengaRu [80]

Answer:

A. 420 J

Explanation:

Given the following data;

Mass = 30.45 g

Specific heat capacity = 4.18 J/g °C.

Temperature = 3.3°C

To find the quantity of heat;

Heat capacity is given by the formula;

$Q = mct$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature.

Substituting into the equation, we have;

$Q = 30.45 * 4.18 * 3.3$

Q = 420.03 ≈ 420 Joules

8 0

3 years ago

A 900 kg car moves around a 500 m radius curve at 25.0 m/s. What is the centripetal force on

Gnesinka [82]

Answer:

9375 N

Explanation:

From the question,

Centripetal force (F) = mv²/r.................. Equation 1

Where m = mass of the car, v = velocity of the car, r = radius of the curve.

Given: m = 900 kg, r = 600 m, v = 25 m/s

Substitute these values into equation 1

F = (900×25²)/600

F = 9375 N.

Hence the centripetal force on the car is 9375 N

3 0

3 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 114m in 30s? m/s

Kitty [74]

3.8 m/s
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5 0

3 years ago