Answer:
The minimum score required for an interview is 77.252
Step-by-step explanation:
We solve this using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Top 15% of the candidates is a ranking that is equivalent to = 100 - 15% = 85th percentile.
The z score of 85th percentile = 1.036
Mean = 70
Standard Deviation = 7
Minimum score = raw score = ???
Hence:
1.036 = x - 70/7
Cross Multiply
1.036 × 7 = x - 70
7.252 = x - 70
x = 70 + 7.252
x = 77.252
The minimum score required for an interview is 77.252
Answer:
i Don't know this but other's can help you.
ASWER.
1/6
FIRST
12 IS THE LOWEST COMMON DENOMINATOR
SECOND
1\3
4/3
=-5/12
THIRD 3 -5/12
= -2/12
=1/6
Answer: 2 2/5 is 4/5 of 3
Step-by-step explanation:
We can view that as what do we multiply 3 by to get 2 2/5 and call that value x
3x = 2 2/5
x = (2 2/5)/3
Let's turn 2 2/5 into an improper fraction... 2 2/5 = 12/5
So we have
x = (12/5)/3 = (12/5)(1/3) = 4/5
Thus 2 2/5 is 4/5 of 3
Verify: 3(4/5) = 12/5 = 2 2/5
