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3 years ago

Which of the following is true because of the Commutative Law of Addition?

Mathematics

1 answer:

Stells [14]3 years ago

5 0

Answer:

2+11+16=11+16+2

Step-by-step explanation:

According to the commutative law of addition,

(A+B)+C=(C+B)+A

i.e.A+B+C=C+B+A

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Someone help pls:( !!!!!!!!!!

lesantik [10]

Answer:

Multiply both sides by -2 and reverse the inequality symbol

Step-by-step explanation:

since it is division you want to make it multiplication so that you can get the answer easier

-1/2w<12

it cancels out the -1/2 than just multiply 12 and -2 you get -24

w > -24

8 0

2 years ago

Simplify the algebraic expression -5(6x)

WINSTONCH [101]

Answer:

-30x

Step-by-step explanation:

The parenthesis is just to multiply, and you can combine like terms. So -5*6=-30, which you multiply with x to get -30x.

5 0

2 years ago

A student was given two data sets, Set A and Set B. Which of the following

Elden [556K]

Answer:

I don't know were the statement are but here are the specs of each set

Step-by-step explanation:

Set A

mean; 83.83333

median; 87.5

mode; it has no mode

range; 147

Set B

mean; 67.08571

median; 3

mode; no mode

range; 376

hope this helps sorry for late answer :)

5 0

2 years ago

Damm [24]

Answer:

5x+10

Step-by-step explanation:

Hope this helps!!! :))

5 0

2 years ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago