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Dmitriy789 [7]
3 years ago
7

What is the value of x? x= ____ units

Mathematics
2 answers:
alekssr [168]3 years ago
6 0

We have similar triangles RST ,TSR and TRQ.The triangles are similar to each other .

Similar triangles have sides in proportion.

In similar triangles TQR and TRS:

\frac{TR}{ST} =\frac{TQ}{TR}

Or,

\frac{x}{9} =\frac{16}{x}

Cross multiplying

x^{2}=16(9)

x^{2}=144

Taking root

x=12.

Vera_Pavlovna [14]3 years ago
3 0
∵ ΔSRQ is a right triangle
and RT⊥SQ
∴ x² = ST * TQ
∴ x² = 9 *16 = 144

∴ x = √144 = 12
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Use the diagram to find lengths. BP is the perpendicular bisector of AC. QC is the
faust18 [17]

Answer:

The length of the side PC is 34 cm.

Step-by-step explanation:

We are given that BP is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD.

Suppose BP = 16 cm and AD = 90 cm.

As, it is given that AD = 90 cm and the three sides AB = BC = CD.

From the figure it is clear that AD = AB + BC + CD

So, AB = \frac{90}{3} = 30 cm

BC = \frac{90}{3} = 30 cm

CD = \frac{90}{3} = 30 cm

Since the triangle, BPC is a right-angled triangle as \anglePBC = 90°, so we can use Pythagoras theorem in this triangle to find the length of the side PC.

Now, the Pythagoras theorem states that;

\text{Hypotenuse}^{2} = \text{Perpendicular}^{2} +\text{Base}^{2}

\text{PC}^{2} = \text{BP}^{2} +\text{BC}^{2}

\text{PC}^{2} = \text{16}^{2} +\text{30}^{2}

\text{PC}^{2} = 256+900 = 1156

\text{PC}=\sqrt{1156}

PC = 34 cm

Hence, the length of the side PC is 34 cm.

4 0
3 years ago
Help!!!i never learned this
andre [41]
I hope this helps you



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4 years ago
Examples of properties communative, associative, and identity?
BlackZzzverrR [31]

Answer:

Communative: 12 x 5= 5 x 12 Associative: (5) + 6 = (8) + 3 Identity: 5 x 1= 5

Step-by-step explanation:

3 0
3 years ago
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Helen Weller invested 10,000 in an account that pays 3% simple interest. how much additional money must be invested in an accoun
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Answer:

3% is 300 in intrest

6% is 600 in intrest

4% is 400 in intrest

Step-by-step explanation:

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3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

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4 years ago
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