Two charged objects have a repulsive force of .080 N. if the charge of both of the objects is doubled, then what is the new forc
1 answer:
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Answer:
minimum stopping distance will be d = 75 m
Explanation:
Maximum force exerted by the bracket is given as
F = 9000 N
now we know that mass of the object is
m = 6000 kg
so the maximum acceleration that truck can have is given as
now for finding minimum stopping distance of the truck
Answer:
u= 20.09 m/s
Explanation:
Given that
m = 0.02 kg
M= 2 kg
h= 0.2 m
Lets take initial speed of bullet = u m/s
The final speed of the system will be zero.
From energy conservation
1/2 m u²+ 0 = 0+ (m+M) g h
m u²=2 (m+M) g h
By putting the values
0.02 x u² = 2 (0.02+2) x 10 x 0.2 ( take g=10 m/s²)
u= 20.09 m/s
