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3 years ago

Elements in Group VIIIA (also known as Group 18, or the noble gases) have

Physics

1 answer:

Sonbull [250]3 years ago

3 0

The answer is C (the same number of valence electrons)

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When you stretch a spring 20 cm past its natural length, it exerts a force of 8

Nastasia [14]

Answer:

40 N/m

Explanation:

F = -kx (This is the Hooke's Law equation)

F is the force the spring exerts = 8 N

-k = spring constant

x = displacement (The distance stretched past it's natural length) = 20cm

x needs to be in meters, and 20 cm is = to 0.2 meters

Finally:

8N = -k (0.2m)

-k = 8N / 0.2 m

k = -40 N/m

6 0

3 years ago

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A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a

Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

Where,

$m_{1,2}$ = Mass of each object

$v_{1,2}$ = Initial Velocity of Each object

$V_f$ = Final Velocity

Our values are given as

$m_1 = 2190Kg$

$v_1 =10.5m/s$

$m_2 = 3220kg$

$V_f = 4.74m/s$

Replacing we have that

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

$(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)$

$v_2 = 0.8224m/s$

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0

3 years ago

Giving brainliest!! if you answer correctly :) (30pts)

AnnZ [28]

Answer:

32000joule.

Explanation:

given

mass. (m)=160kg

speed (v)=20m/s

now

kinetic energy =1/2 (mv²)=1/2 ×{160×20²}=32000joule.

8 0

3 years ago

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Machines A, B, and C do the same amount of work, but they each take a different amount of time. Machine A takes more time as com

Amiraneli [1.4K]

So power is considered as the rate of doing work. Base on the problem given, my analysis is that the machine who finish the work faster is machine C. Therefore, in order to finish the same amount of work in a short period of time you are going to expend the most power. My answer is Machine C.

6 0

3 years ago

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g What is the specific heat of silver? The molar heat capacity of silver is 25.35 J/mol⋅∘C. How much energy would it take to rai

disa [49]

Answer:

38.6 J

Explanation:

c = molar heat capacity of silver = 25.35 J/(mol °C)

m = given mass of silver = 9.00 g

M = Molar mass of silver = 108 g

n = Number of moles of silver

Number of moles of silver are given as

$n=\frac{m}{M}$

$n=\frac{9}{108}$

n = 0.0833

Q = Energy needed to raise the temperature

ΔT = Change in temperature = 18.3 °C

Energy needed to raise the temperature is given as

Q = n c ΔT

Q = (0.0833) (25.35) (18.3)

Q = 38.6 J

5 0

3 years ago