Question

An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?

Answer 1

Answer:

300.16m/s

Explanation:

An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?

note velocity is the change in displacement to time

to find the magnitude of the initial speed ,

we will find the square of the vertical component plus the square of the horizontal component. then we look for the square root

U=$\sqrt{Ux^2+Uy^2}$

U=$\sqrt{260^2+150^2}$

U=90,100^2

U=300.16m/s

means that it covers 300.16m in 1 seconds