An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per secon
1 answer:
Answer:
300.16m/s
Explanation:
An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?
note velocity is the change in displacement to time
to find the magnitude of the initial speed ,
we will find the square of the vertical component plus the square of the horizontal component. then we look for the square root
U=
U=
U=90,100^2
U=300.16m/s
means that it covers 300.16m in 1 seconds
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Answer:
True
Explanation:
The tensile stress, σ, on a solid cylindrical wire is given by the following relationship;
Where;
= The tensile force
= The original cross sectional area of the cylindrical wire = π·R²
R = The radius of the wire
Therefore;
= σ ×
= σ × π × R²
Therefore, the tensile force is directly proportional to the square of the radius of the cylindrical wire, and as the radius of the wire increases, which is by increasing the thickness of the wire, the tensile force is largely increased
The correct option is; True.