Answer:
300.16m/s
Explanation:
An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?
note velocity is the change in displacement to time
to find the magnitude of the initial speed ,
we will find the square of the vertical component plus the square of the horizontal component. then we look for the square root
U=
U=
U=90,100^2
U=300.16m/s
means that it covers 300.16m in 1 seconds
Answer:
54 N
Explanation:
We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.
We have a relation for force between two charges q1,q2 as
Value of k is
On substituting the values into the equation we get,
Hence the force between them is 54 N.
Answer:
Explanation:
Here at thermal equilibrium we can say that thermal energy given by Hot coffee is equal to the thermal energy absorbed by ice cubes
So here we have
now since ice cubes are added into coffee when it is at melting temperature
So here we can say that final temperature of coffee is T degree C
Now we have
here we have
L = 333 kJ/kg = 333 J/g[/tex]
now we have
Answer:
the index of refraction of the coating is 1.33
Explanation:
Given the data in the question;
refraction index of interior portion of the rod η = 1.55
angle of incidence θ = 59.5°
From Snell's law, we know that;
η × sinθ
= η
× sinθ
where η is the index of refraction of the rod ( material 1 )
θ is the angle of incidence
η is the index of refraction in outer coating ( material 2 )
θ is the angle of refraction
so we substitute our values into the equation;
η × sinθ
= η
× sinθ
1.55 × sin( 59.5° ) = η × sin( 90° )
1.55 × 0.861629 = η × 1
1.3355 = η × 1
η = 1.33 { 2 decimal places }
Therefore, the index of refraction of the coating is 1.33