All categories

3 years ago

Which statement is NOT true of molecular orbitals: Select one

Chemistry

1 answer:

trapecia [35]3 years ago

5 0

Answer:

A: Antibonding molecular orbitals are higher in energy than all of the bonding molecular orbitals.

Explanation:

Molecular orbital theory describes covalent bonds in terms of molecular orbitals, which result from interaction of the atomic orbitals of the bonding atoms and are associated with the entire molecule.

A bonding molecular orbital has lower energy and greater stability than the atomic orbitals from which it was formed. An antibonding molecular orbital has higher energy and lower stability than the atomic orbitals from which it was formed.

Electrons in the antibonding molecular orbital have higher energy (and less stability) than they would have in the isolated atoms. On the other hand, electrons in the bonding molecular orbital have less energy (and hence greater stability) than they would have in the isolated atoms.

You might be interested in

Type in the name of the following compounds. Be sure to use the periodic table if needed.

Snowcat [4.5K]

the answer is Sulfur dioxide

8 0

3 years ago

Read 2 more answers

What effects would El Niño most likely have on organisms?

Hunter-Best [27]

Answer:

d) el niño would lead to the death of organisms or populations

Explanation:

7 0

3 years ago

Read 2 more answers

Help! 7th Grade Math!

vagabundo [1.1K]

Answer:

Explanation: Trust me

6 0

3 years ago

16 meters per hour to miles per sec

ss7ja [257]

Answer:

2.76 (full answer) 2.7617e-6

Explanation:

6 0

3 years ago

An environmental scientist developed a new analytical method for the determination of cadmium (cd^2+) in mussels. To validate th

Anettt [7]

Answer:

The method is accurate in the calculation of the $Cu^+2$

Explanation:

As a first step we have to calculate the average concentration of $Cu^+2$ find it by the method.

$\frac{0.782+0.762+0.825+0.838+0.761 }{5} =0.79 ppm$

Then we have to find the standard deviation:

$s=\sqrt{\frac{1}{N-1}\sum_{i=1}^N(x_i-\bar{x})^2}=0.0359$

For the confidence interval we have to use the formula:

μ=Average± $\frac{t*s}{\sqrt{n} }$

Where:

t=t student constant with 95 % of confidence and 5 data=2.78

μ= $0.79$ ± $\frac{2.78*0.0359}{\sqrt{5} }$

upper limit: 0.84

lower limit: 0.75

If we compare the limits of the value obtanied by the method (Figure 1 Red line) with the reference material (Figure 1 blue line) we can see that the values obtained by the method are within the values suggested by the reference material. So, it's method is accurate.

7 0

3 years ago