Considering the Charles' law, the gas would have a temperature of -109.2 C.
<h3>Charles' law</h3>
Finally, Charles' law establishes the relationship between the volume and temperature of a gas sample at constant pressure. This law says that the volume is directly proportional to the temperature of the gas. That is, if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Charles' law is expressed mathematically as:
If you want to study two different states, an initial state 1 and a final state 2, the following is true:
<h3>Temperature of the gas in this case</h3>
In this case, you know:
- P1= 1800 psi
- V1= 10 L
- T1= 20 C= 293 K (being 0 C= 273 K)
- P2= 1800 psi
- V2= 6 L
- T2= ?
You can see that the pressure remains constant, so you can apply Charles's law.
Replacing in the Charles's law:
Solving:
<u><em>T2=163.8 K= -109.2 C</em></u>
The gas would have a temperature of -109.2 C.
Learn more about Charles's law:
brainly.com/question/4147359?referrer=searchResults
<u>Answer:</u>
<u>When an alkyl benzene is heated with strong oxidizing asgents like acidic or alkline KMnO4</u>
<u> or acidified K2Cr2O7</u>
<u>, etc. gives aromatic carboxyllic acid. The alkyl side chain gets oxidised to −COOH</u>
<u> group irrespective of the size of the chain.</u>
Explanation:
Answer:
If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.
Explanation:
Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure
V ∝ 1/P or V₁·P₁ = V₂·P₂
Where:
V₁ = Initial volume
V₂ = Final volume = V₁/2
P₁ = Initial pressure = 832 torr
P₂ = Final pressure = Required
From V₁·P₁ = V₂·P₂ we have,
P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)
P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr
Answer:
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Explanation:
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