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Mekhanik [1.2K]
3 years ago
6

The lab technician you recently hired tells you the following: Boss, an undisturbed sample of saturated clayey soil was brought

to me from the Mission Valley site. I measured the mass of the sample to be 600 grams. I then measured the mass of the sample after placing it in the oven for 24 hrs. I found this mass to be 200 grams. Can you help me determine the water content?" Determine the water content.
Engineering
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

The water of the saturated clayed soil is 66.67 %.

Explanation:

Given;

mass of saturated clayed soil, M_s = 600 g

mass of dry soil sample, M_d = 200 g

mass of water content, M_w = M_s - M_d = 600 g - 200 g = 400 g

The water content is determined as;

M_w(\%)  = \frac{M_s - M_d}{M_s} *100\%\\\\M_w(\%)  = \frac{600-200}{600} *100 \% \\\\M_w(\%)  = 66.67 \%

Therefore, the water of the saturated clayed soil is 66.67 %.

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What are three types of land reform ​
s344n2d4d5 [400]

Answer:

Abolition of intermediaries (rent collectors under the pre-Independence land revenue system); Tenancy regulation (to improve the contractual terms including the security of tenure); A ceiling on landholdings (to redistributing surplus land to the landless);

5 0
2 years ago
Read 2 more answers
An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
Assoli18 [71]

Answer: The exit temperature of the gas in deg C is 32^{o}C.

Explanation:

The given data is as follows.

C_{p} = 1000 J/kg K,   R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

P_{1} = 100 kPa,     V_{1} = 15 m^{3}/s

T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

     P_{1}V_{1} = mRT_{1}

or,         m = \frac{P_{1}V_{1}}{RT_{1}}

                = \frac{100 \times 15}{0.5 \times 300}  

                = 10 kg/s

Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}

(T_{2} - T_{1}) = 5 K

T_{2} = 5 K + 300 K

T_{2} = 305 K

           = (305 K - 273 K)

           = 32^{o}C

Therefore, we can conclude that the exit temperature of the gas in deg C is 32^{o}C.

8 0
3 years ago
Some of our modern kitchen cookware is made of ceramic materials. (a) List at least three important characteristics required of
Alisiya [41]

Answer:

A)

It should be Non- toxic

It should possess high Thermal conductivity

It should have the Required Thermal diffusivity

B)

  • stoneware : This material has good thermal diffusivity and it  is quite affordable and it is used in making pizza stones
  • porcelain: mostly used for mugs and it is non-toxic
  • Pyrex : posses good thermal conductivity used in oven

C)   All the materials are suitable because they serve different purposes when making modern kitchen cookware

Explanation:

A) characteristics required of a ceramic material to be used as a kitchen cookware

  • It should be Non- toxic
  • It should possess high Thermal conductivity
  • It should have the Required Thermal diffusivity

B) comparison of three ceramic materials as to their relative properties

  • stoneware : This material has good thermal diffusivity and it  is quite affordable and it is used in making pizza stones
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C) material most suitable for the cookware.

 All the materials are suitable because they serve different purposes when making modern kitchen cookware

8 0
2 years ago
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210
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Answer:

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Explanation:

specific gravity of fluid A = 1.65

Dynamic viscosity = 210 centipoise

<u>Calculate the kinematic viscosity of Fluid A </u>

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Pa = Pw * Specific gravity =  1000 * 1.65 = 1650 kg/m^3

next : convert dynamic viscosity to kg/m-s

210 centipoise = 0.21 kg/m-s

Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A

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Convert to stokes = 1.2727 stokes

4 0
3 years ago
Air at p=1 atm enters a long tube of length 2.5 m and diameter of 12 mm at an inlet temperature of Tm,i=100oC and mass flowrate
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Answer:

The heat transfer q = 18.32W

Explanation:

In this question, we are asked to calculate the heat entering the tube and also evaluate properties at T =400K

Please check attachment for complete solution and step by step explanation

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