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Mekhanik [1.2K]
3 years ago
6

The lab technician you recently hired tells you the following: Boss, an undisturbed sample of saturated clayey soil was brought

to me from the Mission Valley site. I measured the mass of the sample to be 600 grams. I then measured the mass of the sample after placing it in the oven for 24 hrs. I found this mass to be 200 grams. Can you help me determine the water content?" Determine the water content.
Engineering
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

The water of the saturated clayed soil is 66.67 %.

Explanation:

Given;

mass of saturated clayed soil, M_s = 600 g

mass of dry soil sample, M_d = 200 g

mass of water content, M_w = M_s - M_d = 600 g - 200 g = 400 g

The water content is determined as;

M_w(\%)  = \frac{M_s - M_d}{M_s} *100\%\\\\M_w(\%)  = \frac{600-200}{600} *100 \% \\\\M_w(\%)  = 66.67 \%

Therefore, the water of the saturated clayed soil is 66.67 %.

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Answer:

a)

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b)

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c)

it can run around 722 km when it is full charge.

                                                                                                                                                     

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3 years ago
Tech A says that horsepower is a measurement simply of the amount of work being performed. Tech B says that horsepower can be ca
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Tech B

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6 0
3 years ago
2.) A fluid moves in a steady manner between two sections in a flow
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Answer:

250\ \text{lbm/min}

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v_1 = Specific volume at section 1 = 4\ \text{ft}^3/\text{lbm}

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A_2 = Area of section 2 = 2\ \text{ft}^2

Mass flow rate is given by

m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}

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As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}

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3 0
3 years ago
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Answer:

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steadily =200 kPa

temperature = 20°C

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solution

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Answer:

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